यदि cot4θ + cot2θ = 3 है, तो cosec4θ – cosec2θ = ?

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RRB ALP Previous Paper 2 (Held On: 9 Aug 2018 Shift 2)
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Answer (Detailed Solution Below)

Option 4 : 3
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गणना:

cot4θ + cot2θ = 3

⇒ cos4θ/sin4θ + cos 2θ/sin 2θ 

cos 2θ(cos 2θ+ sin 2θ )/sin4θ = 3 (ल.स.प. लेने पर)

cos 2θ/sin4θ = 3

⇒ cot2θ . cosec2θ = 3

अब, cosec4θ – cosec2θ

⇒ cosec2θ(cosec2θ – 1)

⇒ cosec2θcot2θ = 3

∴ cosec4θ – cosec2θ = 3

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