यदि तीन क्रमागत विषम संख्याओं में पहली संख्या का 1/3 भाग तीसरी संख्या के 1/5 भाग से 2 अधिक है, तो दूसरी संख्या ज्ञात कीजिए।

  1. 21
  2. 23
  3. 25
  4. 19

Answer (Detailed Solution Below)

Option 2 : 23
Free
RRB NTPC Graduate Level Full Test - 01
100 Qs. 100 Marks 90 Mins

Detailed Solution

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दिया गया है:

पहली संख्या का 1/3 भाग तीसरी संख्या के 1/5 भाग से 2 अधिक है। 

गणना:

माना कि तीन क्रमागत विषम संख्याएं क्रमशः x, x + 2 और x + 4 हैं, तो

प्रश्न के अनुसार

x × (1/3) = (x + 4) × (1/5) + 2

⇒ x/3 = (x + 4 + 10)/5

⇒ 5x = 3x + 42

⇒ 5x – 3x = 42

⇒ 2x = 42

⇒ x = 21

∴ दूसरी विषम संख्या है = x + 2 = 21 + 2 = 23 

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