यदि 12 + 22 + 32 + ... + 102 = 385 है, तो (22 + 42 + 6+ ... + 202) किसके बराबर है?

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Haryana CET Previous Year Paper (Held On: 6 Nov 2022 Shift 2)
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  1. 1155
  2. 385 × 385
  3. 770
  4. 1540
  5. उत्तर नहीं देना चाहते हैं।

Answer (Detailed Solution Below)

Option 4 : 1540
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Haryana CET Full Test 1
100 Qs. 100 Marks 105 Mins

Detailed Solution

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दिया गया है :

12 + 22 + 32 + ... + 102 = 385

हल :

⇒  ( 22 + 42 + 62 + ........ + 202 ) :

⇒ ( 1 × 2 )2 + ( 2 × 2 )2 + ............. + ( 2 × 10 )2

⇒ ( 22 × 12 ) + ( 22 × 22 ) + ....... + ( 22 × 102 )

⇒ 22 × ( 12 + 22 + 32 + ... + 10)

⇒  4 × 385 

⇒ 1540

अतः, सही उत्तर "1540" है। 

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