Question
Download Solution PDFदिया गया है कि A और B द्वितीय चतुर्थांश के कोण हैं, sin A =
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है:
sin A =
sin B =
प्रयुक्त सूत्र:
sin2A + cos2B = 1
cos (A − B) = cosAcosB + sinAsinB
गणना:
⇒ चूँकि sin A =
⇒ cosA=
क्योंकि कोण दूसरे चतुर्थांश में हैं, इसलिए
⇒ cosA =
⇒ sin B =
⇒ cosB=
क्योंकि कोण दूसरे चतुर्थांश में हैं, इसलिए
⇒ cosB =
अब, सूत्र के अनुसार,
⇒ cos (A − B) = cosAcosB + sinAsinB =
⇒ अत: cos(A - B) का मान
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