Question
Download Solution PDF1000 kW क्षमता वाले एक इंजन द्वारा 11000 kJ की कुल ऊर्जा वाला ईंधन उपयोग किया जाता है। यदि इंजन 10 सेकंड में सभी ईंधन को जला देता है, तो कितनी ऊर्जा नष्ट हो जाती है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसिद्धांत
एक इंजन की ऊर्जा की गणना इस प्रकार की जाती है:
E = P x t
जहाँ, E = ऊर्जा
P = शक्ति
t = समय
गणना
दिया गया है, शक्ति = 1000 kW
t = 10 सेकंड
E = 1000 x 10
E = 10000 kJ
नष्ट हुई ऊर्जा = कुल ऊर्जा - उपयोग की गई ऊर्जा
नष्ट हुई ऊर्जा = 11,000 − 10,000
नष्ट हुई ऊर्जा = 1000 kJ
Last updated on Jul 18, 2025
-> MPPGCL Junior Engineer Notification 2025 has been released for various fields of post (Advt No. 3233).
-> MPPGCL has announced a total of 90 vacancies for Civil, Mechanical, Electrical, and Electronics Engineering (Junior Engineer).
-> Interested candidates can submit their online application form, from 23rd July to 21st August 2025.
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.