400 N का बल एक प्रक्रिया नियंत्रण वाल्व को खोलने के लिए आवश्यक होता है। तो 70 kPa के नियंत्रण गेज दबाव वाले वाल्व को खोलने के लिए डायाप्राम प्रवर्तक के लिए आवश्यक डायाप्राम का क्षेत्रफल क्या है?

This question was previously asked in
ESE Mechanical 2018 Official Paper
View all UPSC IES Papers >
  1. 0.0095 m2
  2. 0.0086 m2
  3. 0.0057 m2
  4. 0.0048 m2

Answer (Detailed Solution Below)

Option 3 : 0.0057 m2
Free
ST 1: UPSC ESE (IES) Civil - Building Materials
6.5 K Users
20 Questions 40 Marks 24 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

एक वाल्व को खोलने के लिए आवश्यक बल = दबाव × डायाप्राम का क्षेत्रफल 

गणना:

दिया गया है F = 400 N और P = 70 kPa

F = P × A

400 = 70 × 103 × A

A=40070×1000=0.0057m2

Latest UPSC IES Updates

Last updated on Jul 2, 2025

-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10. 

-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.

->  UPSC ESE admit card 2025 for the prelims exam has been released. 

-> The UPSC IES Prelims 2025 will be held on 8th June 2025.

-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.

-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.

More Pascal Law Questions

More Pressure Measurement Questions

Get Free Access Now
Hot Links: teen patti bindaas yono teen patti teen patti neta