F(s) is the Laplace transform of the function

f(t) = 2t2e-t

F (1) is ________ (correct to two decimal places).

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Answer (Detailed Solution Below) 0.48 - 0.52

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Concept:

L(tn)=n!sn+1

L(eat)=1sa

L(tneat)=n!(sa)n+1

Calculation:

f(t) = 2t2e-t

F(s)=L(f(t))=2L(t2et)=2×2!(s+1)2+1=4(s+1)3

F(1)=4(1+1)3=12=0.5

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