For the circuit of the given figure, the value of current I is

This question was previously asked in
UKPSC JE Electrical 2013 Official Paper II (Held on 7 Nov 2015)
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  1. 1.0 A
  2. 0.75 A
  3. 0.5 A
  4. 0.25 A

Answer (Detailed Solution Below)

Option 3 : 0.5 A
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UKPSC JE CE Full Test 1 (Paper I)
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Detailed Solution

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Calculation:

The given circuit is

Marking all the loop

From loop i1

-12 + 6 i1 + 6 i1 = 0

i1 = 1 A

From loop i2

-12 + 6i2 + 6i2 - 12 = 0

12i2 = 24

i2 = 2 A

From loop i3

-12 + 6[i3 + i4] + 12i3 = 0

18i3 + 6i4 = 12      .......(1)

From loop i4

6[i3 + i4] + 12i4 = 0

12i4 + 6i4 + 6i3 = 0

6i3 + 18i4 = 0

i3 = -3i4     .......(2)

from eq 1

18(-3i4) + 6i4 = 12

- 54i4 + 6i4 = 12

- 48i4 = 12

so, 

I = i4 + i3 = 

∴ I = 0.5 A

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