Question
Download Solution PDFFind the smallest number which will be completely divisible by 24, 48 and 60.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Find the smallest number which will be completely divisible by 24, 48, and 60.
Formula used:
LCM (Least Common Multiple)
Calculation:
Prime factorization:
24 = 23 × 3
48 = 24 × 3
60 = 22 × 3 × 5
LCM = 24 × 3 × 5
⇒ LCM = 16 × 3 × 5
⇒ LCM = 240
∴ The correct answer is 240.
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