Question
Download Solution PDFFind the charge and potential difference across C1 of capacitance 1 µF for the given circuit?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Calculating the equivalence capacitance, from the left side.
We can see that C1 and C4 are in parallel
therefore
Ce1 = C1 + C4 ....(1)
Now this equivalence will be in series with C2 capacitor
Calculation:
By equation 1,
⇒ Ce1 = 1 + 1
By equation 2,
⇒ Ce2 = 2/3μF
Thus, the total charge flowing through the circuit
⇒ Q = 2/3 μF × 4V
⇒ Q = 8/3μC
Charge across will the capacitance will be in the ratio of respective capacitance
CeqV = C1V + C2V + C3V
Q1 = Q/2
⇒ Q1 = 4/3 μC
Now potential difference across C1 can be calculated as
⇒ V1 = 4/3V
Last updated on Jun 18, 2025
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