Question
Download Solution PDFConsider an inductor of 2 H with ω = 100 rad/sec and with voltage
v = 10 cos (ωt + 50°) V. The time done current is:
This question was previously asked in
KVS TGT WET (Work Experience Teacher) Official Paper
Answer (Detailed Solution Below)
Option 3 : 0.05 cos (100 t − 40°) A
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Detailed Solution
Download Solution PDFConcept:
The voltage across the inductor is given by,
Calculation:
Given VL(t)=v = 10 cos (ωt + 50°) V
L=2 H ,ω= 100 rad/sec}dt
⇒
=0.05 sin (100 t + 50°) A
=0.05 cos (100 t − 40°) A
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