Compute the standard deviation of the following numbers: 5, 6, 4 and 2

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SSC CGL Tier-II ( JSO ) 2017 Official Paper ( Held On : 22 Feb 2018 )
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  1. 1.7
  2. 2.7
  3. 1.2
  4. 2.2

Answer (Detailed Solution Below)

Option 1 : 1.7
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Detailed Solution

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Given

Number = 5, 6, 4, and 2

Formula used

σ = √[x – x̅)2/n]

x̅ = (x1 + x2 + x3 + x4)/4

σ = Standard deviation

x̅ = Mean

Calculation

Mean = x̅ = (5 + 6 + 4 + 2)/4 = 4.25

x

x – x̅
(x – 4.25)

(X – x̅)2

5

0.75

0.5625

6

1.75

3.0625

4

-0.25

0.0625

2

-2.25

5.0625

Total

 

8.75

⇒ σ = √(8.75)/4

⇒ √2.1875)

Standard deviation of these values is 1.479

 

Standard deviation = It is the square root of the arithmetic mean of the square of deviation of the items from their mean value

σ = √[x – x̅)2/n]

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