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দুটি মূল হল 2 + √5 এবং 2 - √5
অনুসৃত ধারণা:
দ্বিঘাত সমীকরণটি হলো
x2 - (মূলের সমষ্টি)x + মূলের গুণফল = 0
গণনা:
ধরা যাক, দুটি মূল হল A এবং B
⇒ A = 2 + √5 এবং B = 2 - √5
⇒ A + B = 2 + √5 + 2 - √5 = 4
⇒ A × B = (2 + √5)(2 - √5) = 4 - 5 = -1
তাহলে সমীকরণ হল
∴ x 2 - 4x - 1 = 0
দ্বিঘাত সমীকরণের জন্য ax2 + bx + c = 0
বর্গের যোগফল = (-b/a) = 4/1
বর্গ করে পাই = c/a = -1/1
তাই, b = -4
সুতরাং x এর সহগটি ঋণাত্মক হবে।
Last updated on Jul 18, 2025
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