Question
Download Solution PDFযদি 2 cot θ = 3 হয়, তাহলে
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
2cotθ = 3
অনুসৃত সূত্র:
Sinθ = P/H
Cosθ = B/H
Tanθ = P/B
Cotθ = B/P
H2 = P2 + B2
যেখানে P = লম্ব
B = ভূমি
H = অতিভুজ
গণনা:
2cotθ = 3
⇒ cotθ = 3/2
(Cotθ = B/P) এর সাথে তুলনা করলে আমরা পাই
⇒ B = 3
⇒ P = 2
পিথাগোরাসের উপপাদ্য অনুসারে
⇒ H2 = P2 + B2
⇒ H2 = 22 + 32
⇒ H = √13
⇒ Sinθ = 2/√13
⇒ Cosθ = 3/√13
⇒ Tanθ = 2/3
প্রদত্ত সমীকরণে সমস্ত মান বসানো হল:
⇒ (2 - 2)/(2 + 3)
⇒ 0
রাশিটির মান 0
Last updated on Jul 16, 2025
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