40% এবং 20% ক্রমিক ছাড়ের সমতুল্য একক ছাড় কত?

This question was previously asked in
RRB Technician Grade III Official Paper (Held On: 29 Dec, 2024 Shift 1)
View all RRB Technician Papers >
  1. 55% 
  2. 50% 
  3. 60% 
  4. 52%

Answer (Detailed Solution Below)

Option 4 : 52%
Free
General Science for All Railway Exams Mock Test
2.2 Lakh Users
20 Questions 20 Marks 15 Mins

Detailed Solution

Download Solution PDF

প্রদত্ত:

40% এবং 20% ক্রমিক ছাড়ের সমতুল্য একক ছাড়

ব্যবহৃত সূত্র:

একক ছাড় = 1 - (1 - d1) × (1 - d2)

গণনা:

একক ছাড় = 1 - (1 - 0.40) × (1 - 0.20)

⇒ একক ছাড় = 1 - 0.60 × 0.80

⇒ একক ছাড় = 1 - 0.48

⇒ একক ছাড় = 0.52 = 52%

∴ সঠিক উত্তরটি হলো বিকল্প (4)

Alternate Method

 

একক ছাড় = D1 + D2 - (D× D2)/100

⇒ 40 + 20 - 40 × 20 /100 = 60 - 8 = 52%

Latest RRB Technician Updates

Last updated on Jul 16, 2025

-> The Railway RRB Technician Notification 2025 have been released under the CEN Notification - 02/2025.

-> As per the Notice, around 6238 Vacancies is  announced for the Technician 2025 Recruitment. 

-> A total number of 45449 Applications have been received against CEN 02/2024 Tech Gr.I & Tech Gr. III for the Ranchi Region.

-> The Online Application form for RRB Technician is open from 28th June 2025 to 28th July 2025. 

-> The Pay scale for Railway RRB Technician posts ranges from Rs. 19900 - 29200.

-> Prepare for the exam with RRB Technician Previous Year Papers.

-> Candidates can go through RRB Technician Syllabus and practice for RRB Technician Mock Test.

More Discount and MP Questions

More Profit and Loss Questions

Get Free Access Now
Hot Links: teen patti gold real cash teen patti master teen patti master plus teen patti party