An objective function is p(x,y)=3x+9y and constraints are,

x+y8,

x+2y4,

x0,

y0

The maximum value of the objective function is:

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  1. 18
  2. 24
  3. 30
  4. 12

Answer (Detailed Solution Below)

Option 1 : 18
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Detailed Solution

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Concept:

Objective function:

Constraints:

Step 1: Identify the Feasible Region

First, find the intersection points of the constraints to determine the vertices of the feasible region.

  1. Intersection of x + y = 8 and x + 2y = 4 :

    Subtract the first equation from the second:

    Substitute y = -4 into x + y = 8 :

    However, y = -4 violates y \geq 0 , so this intersection is not feasible.

  2. Intersection of x + y = 8 with y = 0 :

    , y = 0 . This gives the point (8, 0) .

  3. Intersection of x + 2y = 4 with x = 0 :

    , x = 0 . This gives the point (0, 2) .

  4. Intersection of x + 2y = 4 with y = 0 :

    , y = 0 . This gives the point (4, 0) .

  5. Origin (0, 0) :

    This point satisfies all constraints.

The feasible vertices are (0, 0) , (4, 0) , and (0, 2) . The point (8, 0) is not feasible because it violates x + 2y \leq 4 .

Step 2: Evaluate the Objective Function at Each Vertex

  1. At (0, 0) :

  2. At (4, 0) :

  3. At (0, 2) :

The maximum value of the objective function is the largest value obtained from the feasible vertices, which is 18 at the point (0, 2) .

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