Question
Download Solution PDFA tuning fork A of frequency 384 Hz gives 6 beats in 2 second when sounded with another tuning fork B. The frequency of B could be?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- When two sound waves of slightly different frequencies, travelling in a medium along the same direction, superimpose on each other, the intensity of the resultant sound at a particular position rises and falls regularly with time.
- This phenomenon of regular variation in the intensity of sound with time at a particular position is called beats.
- Beat frequency: The number of beats produced per second is called a beat frequency.
Beat frequency = number of beats/sec
- If n1 and n2 are the frequency of two sources, then the difference in frequencies of two sources
m = (n1 - n2) or (n2 – n1)
Where m = beat frequency
Calculation:
Given Fork A = 384 Hz, 6 beats are produced in 2 seconds
Thus beat frequency
Beat frequency b = ∣fA−fB∣
∴ 3 = ∣384−fB∣
Thus fB = 384 – 3 = 381 Hz or fB = 384 + 3 = 387 Hz
So, The frequency of B can either be 381 Hz or 387 Hz
Last updated on Jul 12, 2025
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