Question
Download Solution PDFA single-phase transmission line of impedance j0.8 ohm supplies a resistive load of 500 A at 300 V. The sending end power factor is ________
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven: Impedance = j0.8 Ω, Current = 500 A, Voltage = 300 V
We know that
VS = VR + IZS
Here VS = Sending voltage, VR = Receiving end voltage, ZS = Line impedance
VS = VR + IZS = 300 + 500 × 0.8j = 300 + 400j = 500∠53.13°
Power factor = cos 53.13° = 0.6 lagging
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