A sample of Si is doped with 1017 donor atoms/cm3. Considering electron mobility in the doped Si 700 cm2/V-sec, the approximate resistivity of the doped Si is

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  1. 1 Ω-cm 
  2. 10 Ω-cm 
  3. 0.1 Ω-cm 
  4. 100 Ω-cm 

Answer (Detailed Solution Below)

Option 3 : 0.1 Ω-cm 
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ISRO Scientist Electronics Full Test - 1
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Detailed Solution

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Concept

For a semiconductor slab doped with excess carriers and placed in an electric field, the current equation is given by:-

J = σ E

Where J = Current Density

σ = Conductivity of the semiconductor defined as:

σ = qnμn + qpμp

n = excess electrons contributing to the current conduction.

p = excess holes contributing to the current conduction.

Also, the Resistivity is defined as the reciprocal of conductivity.

i.e. 

Calculation:

Since the intrinsic carrier concentration of Germanium is of the order of 1013, and the given donor density is of the order of 1020, we can write:

n0 = Nd = 1017 atoms/cm3

μn = 700 cm2/V-sec

Since there is no acceptor impurity, p0 << n0 and can be easily neglected and the resistivity becomes:

ρ = 0.089 Ω-cm  ≈ 0.1 Ω-cm 

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