A platinum RTD has a resistance of 100 ohms at 100°C. If the temperature coefficient is 0.004 / °C, what would be the change in resistance if the temperature rise is 50 °C?

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UGC NET Paper 2: Electronic Science June 2019 Official Paper
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  1. 10 Ω
  2. 15 Ω
  3. 20 Ω
  4. 25 Ω

Answer (Detailed Solution Below)

Option 3 : 20 Ω
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UGC NET Paper 1: Held on 21st August 2024 Shift 1
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Detailed Solution

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Concept:

The resistance of the conductor changes when the temperature of that conductor changes.

New resistance is given by:

\({{R}_{t}}={{R}_{0}}\left( 1+α \text{ }\!\!Δ\!\!\text{ }T \right)\)

Where Rt = the resistance of the conductor after temperature changes

R= the resistance of the conductor before temperature changes

α = temperature coefficient

ΔT = final temperature – initial temperature

Calculation:

Given:

RO = 100 ohm

α =  0.004 / °C

ΔT = 100°C - 50°C = 50°C

Rt = 100(1 + 0.004 x 50)

Rt = 120 ohm

So total change in resistance is: 

ΔR = 120 - 100 = 20 Ohm

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