Question
Download Solution PDFA Norton circuit with 10 A current source and 15 Ω resistance is connected across a resistance of 5 Ω. The current in 5 Ω resistance will be-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFNorton Theorem
Norton's theorem states that it is possible to simplify any linear circuit, into an equivalent circuit with a single current source and a parallel resistance.
Current divider rule
When two resistances are connected in parallel, the current is divided as:
\(I_1={R_2\over R_1+R_2}\times I\)
\(I_2={R_1\over R_1+R_2}\times I\)
Calculation
The current through 5Ω resistance is given by:
\(I_L={15\over 15+5}\times 10\)
IL = 7.5 A
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