A field is in the shape of a rhombus, whose perimeter is 292 m and one of its diagonals is 96 m. What is the area of the field?

Question

Question

This question was previously asked in

RRB NTPC CBT 2 (Level-3) Official Paper (Held On: 14 June 2022 Shift 2)

Answer 1

Given:

A field is in the shape of a rhombus, whose perimeter is 292 m and one of its diagonals is 96 m.

Concept used:

Area of a rhombus = Product of the lengths of two diagonals ÷ 2

In the case of Rhombus,

Side² =

Calculation:

Let the other diagonal be D.

According to the question,

73² = (96/2)² + (D/2)²

⇒ (D/2)2 = 73² - 48²

⇒ (D/2)2 = 3025

⇒ (D/2)2 = 55²

⇒ D/2 = 55

⇒ D = 110

Hence, the area of the rhombus field = = 5280 cm²

∴ The area of the field is 5280 cm2.

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