A charged particle falls perpendicularly into a uniform magnetic field and traces a circular path. The relationship between radius r of the circular path and KE of the particle is given as-

  1. r ∝ KE2
  2. r ∝ KE-1
  3. r2 ∝ KE3
  4. r ∝ 

Answer (Detailed Solution Below)

Option 4 : r ∝ 
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Detailed Solution

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The correct answer is option 4) i.e. r ∝

CONCEPT:

  • Magnetic force: Magnetic force is the force experienced by electrically charged particles moving in a magnetic field.
    • The magnitude of the magnetic force (F) on a charge (q) moving at a speed (v) in a magnetic field of strength B is given by: 

Where θ is the angle enclosing v and B. 

  • Right-hand rule: The magnetic force acting on a moving charged particle is always perpendicular to the plane formed by v and B and follows the right-hand rule.

  • When a charged particle moves perpendicular to the magnetic field (θ = 90), it follows a curved path and undergoes circular motion.
  • Here, the magnetic force supplies the centripetal force which keeps the particle in a circular motion.

Magnetic force,  

​Where m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circular path traced by the particle.

EXPLANATION:

The kinetic energy of a particle is given by 

Where m is the mass and v is its velocity.

      ----(1)

The magnetic force experienced by the particle

      ----(2)

Substituting (1) in (2),

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