Question
Download Solution PDFA, B and C can finish a work in 15 days working alternately in the same order. The efficiency of A is the same as that of B, and the efficiency of C is equal to that of A. In how many days will the work be finished if they work alternately in the order C, A and B?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Efficiency of A = Efficiency of B
Efficiency of C = Efficiency of A
Formula used:
Total work = efficiency × time
Calculation:
According to the question:
Efficiency of A = efficiency of B = efficiency of C
A, B and C can finish a work in 15 days working alternately.
⇒ 3 days = (1 + 1 + 1) = 3 units of work
⇒ 3 × 5 = 15 days = 3 × 5 = 15 units of work
Now, C,A and B can do the work alternately then,
⇒ (1 + 1 + 1) = 3 units of work = 3 days
⇒ 3 × 5 = 15 units of work = 3 × 5 = 15 days
∴ The correct answer is 15 days.
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