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Latest Signal Flow Graph and Block Diagram MCQ Objective Questions

Top Signal Flow Graph and Block Diagram MCQ Objective Questions

Signal Flow Graph and Block Diagram Question 1:

A signal flow graph of a system is shown below.

Which of the following statements regarding the Signal flow graph is correct?

  1. It has two forward paths and five individual loops.
  2. It has three forward paths and three pairs of two non-touching loops.
  3. The total no. of individual loops and the no. of pairs of two non-touching loops are reduced by equal no. if the branch of SFG having gain G6 is removed.
  4. There are three pairs of two non-touching loops.

Answer (Detailed Solution Below)

Option :

Signal Flow Graph and Block Diagram Question 1 Detailed Solution

There are two forward paths in the given SFG.

P1 = G1 G2 G3 G4

P2 = G1 G5 G8 G4

There are five individual loops, given as

L1 = G1 G2 G9

L2 = G3 G4 G10

L3 = G1 G5 G8 G4 G10 G9

L4 = G5 G6

L5 = G7

There are three possible combinations of two non-touching loops,

L1 and L5, i.e. L15 = G1 G2 G9 G7

L2 and L4, i.e. L24 = G3 G4 G10 G5 G6

L2 and L5, i.e. L25 = G3 G4 G10 G7

After removing the branch having gain G6 i.e. putting G6 = 0,

Loop L4 is removed so, the total number of loops reduced by 1 and remains four loops.

The Loop pair of two non-touching loops L24 is also removed, so pairs of two non-touching loops are reduced by 1 and remains two pairs.

Mistake Points

Forward path. A path from an input node to an output node that does not re-visit any node.

G1 G5 G6 G2 G3 G4 is not a forward path as a node is visited twice. 

Signal Flow Graph and Block Diagram Question 2:

The DC gain of the filter shown below is –

Answer (Detailed Solution Below) -0.5

Signal Flow Graph and Block Diagram Question 2 Detailed Solution

P1 = -2

1 = 1

2 = 1

For DC gain, put s = 0

Signal Flow Graph and Block Diagram Question 3:

The transfer function of the given diagram is___

Answer (Detailed Solution Below)

Option 3 :

Signal Flow Graph and Block Diagram Question 3 Detailed Solution

Concept:

A signal flow graph is a graphical representation of the relationships between the variables of a set of linear algebraic equations.

Manson's gain formula:

  • Where Pk is the forward path transmittance of kth in the path from a specified input is known to an output node. In arresting Pk no node should be encountered more than once.
  • Δ is called the signal flow graph determinant.
  • Δ = 1 – (sum of all individual loop transmittances) + (sum of loop transmittance products of all possible pair of non-touching loops) – (sum of loop transmittance products of all possible triplets of non-touching loops) + (……) – (……)
  • Δ k is the factor associated with the concerned path and involves all closed loop in the graph which are isolated from the forward path under consideration.
  • The path factor Δk for the kth path is equal to the value of the grab determinant of its signal flow graph which exists after erasing the Kth path from the graph.

 

Explanation:

There are two forward paths, G1 and G2

∴ Pk = G1 + G2

Δ= 1 

There are two loop, G1H1 and G2H1

∴ Δ = 1 - G1H1 - G2H1

By using mason’s gain formula, the transfer will be 

Signal Flow Graph and Block Diagram Question 4:

In the signal flow graph of figure given below, the gain C/R will be

  1. 11/9
  2. 22/15
  3. 24/23
  4. 44/23

Answer (Detailed Solution Below)

Option 4 : 44/23

Signal Flow Graph and Block Diagram Question 4 Detailed Solution

Concept:
Mason’s Gain Formula
  • It is a technique used for finding the transfer function of a control system. A formula that determines the transfer function of a linear system by making use of the signal flow graph is known as Mason’s Gain Formula.
  • It shows its significance in determining the relationship between input and output.

 

Suppose there are ‘N’ forward paths in a signal flow graph. The gain between the input and the output nodes of a signal flow graph is nothing but the transfer function of the system. It can be calculated by using Mason’s gain formula.

Mason’s gain formula is

Where,

C(s) is the output node

R(s) is the input node

T is the transfer function or gain between R(s) and C(s)

Pi is the ith forward path gain

Δ = 1−(sum of all individual loop gains) + (sum of gain products of all possible two non-touching loops) − (sum of gain products of all possible three non-touching loops) + ........

Δi is obtained from Δ by removing the loops which are touching the ith forward path.

Calculations:

The forward paths are as follows:

P1 = 5

P2 = 2 × 3 × 4 = 24

The loops are as follows:

L1 = -2, L2 = -3, L3 = -4, L4 = -5

The two non-touching loops are:

L1L3 = 8

There is no three non-touching loops

By Mason’s gain formula:-

 

 

Signal Flow Graph and Block Diagram Question 5:

The given signal flow graph represents.

  1. An integrator with a gain 2
  2. A differentiator with a gain 2
  3. A differentiator with a gain of 0.5
  4. An integrator with a gain of 0.5

Answer (Detailed Solution Below)

Option 4 : An integrator with a gain of 0.5

Signal Flow Graph and Block Diagram Question 5 Detailed Solution

Number of forward paths = 2

 

 

Number of loops = 1

 

 

 

Δ1 = 1

The transfer function is,

 

 

 

It represents an integrator with a gain of 0.5.

Signal Flow Graph and Block Diagram Question 6:

The block diagram of a control system is shown in figure. The magnitude of the transfer function is

Answer (Detailed Solution Below) 0.7 - 0.75

Signal Flow Graph and Block Diagram Question 6 Detailed Solution

Forward path = 8

Loops = +8, 4

Δ = 1 – (8 + 4) = -11

Transfer function 

Signal Flow Graph and Block Diagram Question 7:

A feedback control system is shown in the figure.

The number of all possible combinations of non-touching loops taken two at a time is ______.

Answer (Detailed Solution Below) 2

Signal Flow Graph and Block Diagram Question 7 Detailed Solution

Let us first draw the SFG.

At every summing and take-off point or pick-off point, we will consider nodes.

The SFG along with the loops marked can be drawn as follows:

Loops:

Two non-touching loops are:

The correct answer is 2.

Signal Flow Graph and Block Diagram Question 8:

For the signal flow graph shown in Fig., the value of X3/X1 is ______.

  1. 40
  2. 20
  3. 5
  4. 10

Answer (Detailed Solution Below)

Option 2 : 20

Signal Flow Graph and Block Diagram Question 8 Detailed Solution

Concept:
Mason’s Gain Formula
  • It is a technique used for finding the transfer function of a control system. A formula that determines the transfer function of a linear system by making use of the signal flow graph is known as Mason’s Gain Formula.
  • It shows its significance in determining the relationship between input and output.
  • Suppose there are ‘N’ forward paths in a signal flow graph. The gain between the input and the output nodes of a signal flow graph is nothing but the transfer function of the system. It can be calculated by using Mason’s gain formula.

 

Mason’s gain formula is

Where,

C(s) is the output node

R(s) is the input node

T is the transfer function or gain between R(s) and C(s)

Pi is the ith forward path gain

Δ = 1−(sum of all individual loop gains) + (sum of gain products of all possible two non-touching loops) − (sum of gain products of all possible three non-touching loops) + ........

Δi is obtained from Δ by removing the loops which are touching the ith forward path.

Calculation:

No of forward paths = 1

Forward Path Gain (P1) = 10 × 1 = 10

No of individual loops = 1

The gain of the individual loops = 0.5

No of two non-touching loop gains = 0

∴ Δ = 1 – (0.5) = 0.5, Δ1 = 1

The transfer function for given signal flow graph is given as

Signal Flow Graph and Block Diagram Question 9:

Find the transfer function  of the system given below

Answer (Detailed Solution Below)

Option 3 :

Signal Flow Graph and Block Diagram Question 9 Detailed Solution

Concept:

Mason’s gain formula is

Where,

C(s) is the output node

R(s) is the input node

T is the transfer function or gain between R(s) and C(s)

Pi is the ith forward path gain

Δ = 1−(sum of all individual loop gains) + (sum of gain products of all possible two non-touching loops) − (sum of gain products of all possible three non-touching loops) + ........

Δi is obtained from Δ by removing the loops which are touching the ith forward path.

Calculation:

Given block diagram is,

There are two forward paths,

Δ1P1 = G1, Δ2P2 = G2

There are two loops,

- G1H, - G2H

Δ = 1 - (- G1H - G2H) = 1 + H (G1 + G2)

From mason's gain formula

 

Signal Flow Graph and Block Diagram Question 10:

In a signal-flow graph, nodes are represented by small-

  1. Arrows
  2. Squares
  3. Pointers
  4. Circles

Answer (Detailed Solution Below)

Option 4 : Circles

Signal Flow Graph and Block Diagram Question 10 Detailed Solution

Concept:

  • From the above signal flow diagram, the circle represents the nodes.
  • Arrows represent the path in the signal flow.

Additional Information

Forward path: Path from the input node to the output node.

Here 5,3,2 is a forward path.



Feedback loops: A closed path originates at one node and terminates at the same node. So that no node should be touched twice.

Here 3, - 3 is feedback loops.


Non-touching loops: Loops with no common node.

Here 

Touching loops: Loops with at least one touching loop.

Here  

Confusion Points Here, the pointer means asterisk (*), not the full stop point.

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