Tabulation and Pie Chart MCQ Quiz - Objective Question with Answer for Tabulation and Pie Chart - Download Free PDF
Last updated on Jun 26, 2025
Latest Tabulation and Pie Chart MCQ Objective Questions
Tabulation and Pie Chart Question 1:
Comprehension:
Directions: Study the information carefully and answer the questions.
The pie chart given below shows the percentage distribution of total characters (heroes + villains) introduced by Author Z across four chapters of their new fantasy novel. The table that follows depicts by how much more or less the number of heroes introduced is compared to the number of villains in each of these chapters.
Note: A total of 5 heroes were introduced in Chapter One.
| Chapters | The number of heroes introduced is how much more or less compared to the number of villains |
| Chapter 1 | 66.66% |
| Chapter 2 | -40% |
| Chapter 3 | 0 |
| Chapter 4 | -66.66% |
Finally, the total number of heroes introduced across Chapters One and Two is approximately what percentage of the total number of characters introduced across Chapters Four and Three?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 1 Detailed Solution
General Solution:
We are given percentage distribution of total characters in each chapter as:
Chapter 1 = p/2%
Chapter 2 = 2p%
Chapter 3 = 3p%
Chapter 4 = 5(p − 1)%
Add all percentages to get total = 100%
⇒ p/2 + 2p + 3p + 5(p − 1) = 100
⇒ (p/2 + 2p + 3p + 5p − 5) = 100
⇒ (10.5p − 5) = 100
⇒ 10.5p = 105
⇒ p = 10
Now find % of total characters per chapter:
Chapter 1 = p/2 = 10/2 = 5%
Chapter 2 = 2p = 20%
Chapter 3 = 3p = 30%
Chapter 4 = 5(p − 1) = 5 × 9 = 45%
Given: In Chapter 1, 5 heroes were introduced
If heroes = 5 and heroes are 66.66% more than villains:
⇒ Let villains = x ⇒ 5 = x + (66.66% of x) = x + (2/3)x = (5/3)x
⇒ x = 3 ⇒ Villains = 3
⇒ Total characters in Chapter 1 = 5 + 3 = 8
Since 5% = 8 characters ⇒ Total characters = 8 ÷ 0.05 = 160
Characters per chapter
Chapter 1 = 5% of 160 = 8 (Already known: Heroes = 5, Villains = 3)
Chapter 2 = 20% of 160 = 32
Chapter 3 = 30% of 160 = 48
Chapter 4 = 45% of 160 = 72
Chapter 2: Heroes are 40% LESS than villains
Let villains = x ⇒ heroes = x − 40% of x = 0.6x
Total = x + 0.6x = 1.6x = 32
⇒ x = 32 ÷ 1.6 = 20 ⇒ Heroes = 0.6 × 20 = 12
Chapter 2: Heroes = 12, Villains = 20
Chapter 3: Heroes = Villains
Total = 48 ⇒ Heroes = 24, Villains = 24
Chapter 4: Heroes are 66.66% LESS than villains
⇒ Heroes = x, Villains = x + 66.66% of x = x + (2/3)x = (5/3)x
Total = x + (5/3)x = (8/3)x = 72
⇒ x = 72 × (3 ÷ 8) = 27
⇒ Villains = 72 − 27 = 45
Chapter 4: Heroes = 27, Villains = 45
Thus,
| Chapter | Heroes | Villains | Total |
|---|---|---|---|
| Chapter 1 | 5 | 3 | 8 |
| Chapter 2 | 12 | 20 | 32 |
| Chapter 3 | 24 | 24 | 48 |
| Chapter 4 | 27 | 45 | 72 |
Total characters introduced = 160
Calculations:
From earlier calculations:
Chapter 1: Heroes = 5
Chapter 2: Heroes = 12
Chapter 3: Total characters = 48
Chapter 4: Total characters = 72
Total heroes in Chapters 1 and 2 = 5 + 12 = 17
Total characters in Chapters 3 and 4 = 48 + 72 = 120
Find the required percentage
⇒ (17 ÷ 120) × 100 = 14.1666%
Thus, the correct answer is pproximately 14.17%
Tabulation and Pie Chart Question 2:
Comprehension:
Directions: Study the information carefully and answer the questions.
The pie chart given below shows the percentage distribution of total characters (heroes + villains) introduced by Author Z across four chapters of their new fantasy novel. The table that follows depicts by how much more or less the number of heroes introduced is compared to the number of villains in each of these chapters.
Note: A total of 5 heroes were introduced in Chapter One.
| Chapters | The number of heroes introduced is how much more or less compared to the number of villains |
| Chapter 1 | 66.66% |
| Chapter 2 | -40% |
| Chapter 3 | 0 |
| Chapter 4 | -66.66% |
The number of villains introduced by Author Y in Chapter One is 66.67% less than those in Chapter Four by Author Z. The total number of characters introduced in Chapter One by Author Y is equal to the average number of characters introduced by Author Z in Chapters One and Two. Find the difference between the heroes and villains introduced in Chapter One by Author Y.
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 2 Detailed Solution
General Solution:
We are given percentage distribution of total characters in each chapter as:
Chapter 1 = p/2%
Chapter 2 = 2p%
Chapter 3 = 3p%
Chapter 4 = 5(p − 1)%
Add all percentages to get total = 100%
⇒ p/2 + 2p + 3p + 5(p − 1) = 100
⇒ (p/2 + 2p + 3p + 5p − 5) = 100
⇒ (10.5p − 5) = 100
⇒ 10.5p = 105
⇒ p = 10
Now find % of total characters per chapter:
Chapter 1 = p/2 = 10/2 = 5%
Chapter 2 = 2p = 20%
Chapter 3 = 3p = 30%
Chapter 4 = 5(p − 1) = 5 × 9 = 45%
Given: In Chapter 1, 5 heroes were introduced
If heroes = 5 and heroes are 66.66% more than villains:
⇒ Let villains = x ⇒ 5 = x + (66.66% of x) = x + (2/3)x = (5/3)x
⇒ x = 3 ⇒ Villains = 3
⇒ Total characters in Chapter 1 = 5 + 3 = 8
Since 5% = 8 characters ⇒ Total characters = 8 ÷ 0.05 = 160
Characters per chapter
Chapter 1 = 5% of 160 = 8 (Already known: Heroes = 5, Villains = 3)
Chapter 2 = 20% of 160 = 32
Chapter 3 = 30% of 160 = 48
Chapter 4 = 45% of 160 = 72
Chapter 2: Heroes are 40% LESS than villains
Let villains = x ⇒ heroes = x − 40% of x = 0.6x
Total = x + 0.6x = 1.6x = 32
⇒ x = 32 ÷ 1.6 = 20 ⇒ Heroes = 0.6 × 20 = 12
Chapter 2: Heroes = 12, Villains = 20
Chapter 3: Heroes = Villains
Total = 48 ⇒ Heroes = 24, Villains = 24
Chapter 4: Heroes are 66.66% LESS than villains
⇒ Heroes = x, Villains = x + 66.66% of x = x + (2/3)x = (5/3)x
Total = x + (5/3)x = (8/3)x = 72
⇒ x = 72 × (3 ÷ 8) = 27
⇒ Villains = 72 − 27 = 45
Chapter 4: Heroes = 27, Villains = 45
Thus,
| Chapter | Heroes | Villains | Total |
|---|---|---|---|
| Chapter 1 | 5 | 3 | 8 |
| Chapter 2 | 12 | 20 | 32 |
| Chapter 3 | 24 | 24 | 48 |
| Chapter 4 | 27 | 45 | 72 |
Total characters introduced = 160
Calculations:
From earlier data of Author Z:
Chapter 1: Total = 8 (Heroes = 5, Villains = 3)
Chapter 2: Total = 32 (Heroes = 12, Villains = 20)
Chapter 4: Villains = 45
Total characters in Chapter 1 by Author Y:
Given: Equal to average of Z’s Chapter 1 and 2
⇒ (8 + 32) ÷ 2 = 40 ÷ 2 = 20 characters
Villains in Chapter 1 by Author Y:
Given: 66.67% less than villains in Z’s Chapter 4
Villains in Z’s Chapter 4 = 45
66.67% less = (2/3) less ⇒ So remaining = 1/3 of 45 = 15
Villains = 15
Heroes in Chapter 1 by Author Y:
Total = 20, Villains = 15 ⇒ Heroes = 20 − 15 = 5
Required Difference = 15 - 5 = 10
Thus, the correct answer is 10.
Tabulation and Pie Chart Question 3:
Comprehension:
Directions: Study the information carefully and answer the questions.
The pie chart given below shows the percentage distribution of total characters (heroes + villains) introduced by Author Z across four chapters of their new fantasy novel. The table that follows depicts by how much more or less the number of heroes introduced is compared to the number of villains in each of these chapters.
Note: A total of 5 heroes were introduced in Chapter One.
| Chapters | The number of heroes introduced is how much more or less compared to the number of villains |
| Chapter 1 | 66.66% |
| Chapter 2 | -40% |
| Chapter 3 | 0 |
| Chapter 4 | -66.66% |
The number of magical creatures introduced in Chapter One is twice the difference between the heroes and villains introduced in that chapter. In Chapter Four, the number of magical creatures introduced is 25% more than in Chapter One. Find the difference between the number of magical creatures and the number of villains introduced in Chapter Four.
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 3 Detailed Solution
General Solution:
We are given percentage distribution of total characters in each chapter as:
Chapter 1 = p/2%
Chapter 2 = 2p%
Chapter 3 = 3p%
Chapter 4 = 5(p − 1)%
Add all percentages to get total = 100%
⇒ p/2 + 2p + 3p + 5(p − 1) = 100
⇒ (p/2 + 2p + 3p + 5p − 5) = 100
⇒ (10.5p − 5) = 100
⇒ 10.5p = 105
⇒ p = 10
Now find % of total characters per chapter:
Chapter 1 = p/2 = 10/2 = 5%
Chapter 2 = 2p = 20%
Chapter 3 = 3p = 30%
Chapter 4 = 5(p − 1) = 5 × 9 = 45%
Given: In Chapter 1, 5 heroes were introduced
If heroes = 5 and heroes are 66.66% more than villains:
⇒ Let villains = x ⇒ 5 = x + (66.66% of x) = x + (2/3)x = (5/3)x
⇒ x = 3 ⇒ Villains = 3
⇒ Total characters in Chapter 1 = 5 + 3 = 8
Since 5% = 8 characters ⇒ Total characters = 8 ÷ 0.05 = 160
Characters per chapter
Chapter 1 = 5% of 160 = 8 (Already known: Heroes = 5, Villains = 3)
Chapter 2 = 20% of 160 = 32
Chapter 3 = 30% of 160 = 48
Chapter 4 = 45% of 160 = 72
Chapter 2: Heroes are 40% LESS than villains
Let villains = x ⇒ heroes = x − 40% of x = 0.6x
Total = x + 0.6x = 1.6x = 32
⇒ x = 32 ÷ 1.6 = 20 ⇒ Heroes = 0.6 × 20 = 12
Chapter 2: Heroes = 12, Villains = 20
Chapter 3: Heroes = Villains
Total = 48 ⇒ Heroes = 24, Villains = 24
Chapter 4: Heroes are 66.66% LESS than villains
⇒ Heroes = x, Villains = x + 66.66% of x = x + (2/3)x = (5/3)x
Total = x + (5/3)x = (8/3)x = 72
⇒ x = 72 × (3 ÷ 8) = 27
⇒ Villains = 72 − 27 = 45
Chapter 4: Heroes = 27, Villains = 45
Thus,
| Chapter | Heroes | Villains | Total |
|---|---|---|---|
| Chapter 1 | 5 | 3 | 8 |
| Chapter 2 | 12 | 20 | 32 |
| Chapter 3 | 24 | 24 | 48 |
| Chapter 4 | 27 | 45 | 72 |
Total characters introduced = 160
Calculations:
Chapter One: Heroes = 5, Villains = 3
Chapter Four: Villains = 45
Magical creatures in Chapter One = 2 × (Heroes − Villains)
⇒ 2 × (5 − 3) = 2 × 2 = 4
Magical creatures in Chapter Four = 25% more than in Chapter One
⇒ 4 + 25% of 4 = 4 + 1 = 5
Magical creatures in Chapter Four = 5
Villains in Chapter Four = 45
⇒ Difference = 45 − 5 = 40
Thus, the correct answer is 40.
Tabulation and Pie Chart Question 4:
Comprehension:
Directions: Study the information carefully and answer the questions.
The pie chart given below shows the percentage distribution of total characters (heroes + villains) introduced by Author Z across four chapters of their new fantasy novel. The table that follows depicts by how much more or less the number of heroes introduced is compared to the number of villains in each of these chapters.
Note: A total of 5 heroes were introduced in Chapter One.
| Chapters | The number of heroes introduced is how much more or less compared to the number of villains |
| Chapter 1 | 66.66% |
| Chapter 2 | -40% |
| Chapter 3 | 0 |
| Chapter 4 | -66.66% |
The total number of characters introduced in Chapter One is given as (x – 20), and those in Chapter Three as (y + 8). Calculate the average value of x and y.
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 4 Detailed Solution
General Solution:
We are given percentage distribution of total characters in each chapter as:
Chapter 1 = p/2%
Chapter 2 = 2p%
Chapter 3 = 3p%
Chapter 4 = 5(p − 1)%
Add all percentages to get total = 100%
⇒ p/2 + 2p + 3p + 5(p − 1) = 100
⇒ (p/2 + 2p + 3p + 5p − 5) = 100
⇒ (10.5p − 5) = 100
⇒ 10.5p = 105
⇒ p = 10
Now find % of total characters per chapter:
Chapter 1 = p/2 = 10/2 = 5%
Chapter 2 = 2p = 20%
Chapter 3 = 3p = 30%
Chapter 4 = 5(p − 1) = 5 × 9 = 45%
Given: In Chapter 1, 5 heroes were introduced
If heroes = 5 and heroes are 66.66% more than villains:
⇒ Let villains = x ⇒ 5 = x + (66.66% of x) = x + (2/3)x = (5/3)x
⇒ x = 3 ⇒ Villains = 3
⇒ Total characters in Chapter 1 = 5 + 3 = 8
Since 5% = 8 characters ⇒ Total characters = 8 ÷ 0.05 = 160
Characters per chapter
Chapter 1 = 5% of 160 = 8 (Already known: Heroes = 5, Villains = 3)
Chapter 2 = 20% of 160 = 32
Chapter 3 = 30% of 160 = 48
Chapter 4 = 45% of 160 = 72
Chapter 2: Heroes are 40% LESS than villains
Let villains = x ⇒ heroes = x − 40% of x = 0.6x
Total = x + 0.6x = 1.6x = 32
⇒ x = 32 ÷ 1.6 = 20 ⇒ Heroes = 0.6 × 20 = 12
Chapter 2: Heroes = 12, Villains = 20
Chapter 3: Heroes = Villains
Total = 48 ⇒ Heroes = 24, Villains = 24
Chapter 4: Heroes are 66.66% LESS than villains
⇒ Heroes = x, Villains = x + 66.66% of x = x + (2/3)x = (5/3)x
Total = x + (5/3)x = (8/3)x = 72
⇒ x = 72 × (3 ÷ 8) = 27
⇒ Villains = 72 − 27 = 45
Chapter 4: Heroes = 27, Villains = 45
Thus,
| Chapter | Heroes | Villains | Total |
|---|---|---|---|
| Chapter 1 | 5 | 3 | 8 |
| Chapter 2 | 12 | 20 | 32 |
| Chapter 3 | 24 | 24 | 48 |
| Chapter 4 | 27 | 45 | 72 |
Total characters introduced = 160
Calculations:
From the previous solution:
Total characters in Chapter One = 8
Total characters in Chapter Three = 48
Chapter 1 total characters = x − 20 ⇒ x − 20 = 8 ⇒ x = 28
Chapter 3 total characters = y + 8 ⇒ y + 8 = 48 ⇒ y = 40
Average of x and y:
⇒ (x + y) ÷ 2 = (28 + 40) ÷ 2 = 68 ÷ 2 = 34
Thus, the correct answer is 34.
Tabulation and Pie Chart Question 5:
Comprehension:
Directions: Study the information carefully and answer the questions.
The pie chart given below shows the percentage distribution of total characters (heroes + villains) introduced by Author Z across four chapters of their new fantasy novel. The table that follows depicts by how much more or less the number of heroes introduced is compared to the number of villains in each of these chapters.
Note: A total of 5 heroes were introduced in Chapter One.
| Chapters | The number of heroes introduced is how much more or less compared to the number of villains |
| Chapter 1 | 66.66% |
| Chapter 2 | -40% |
| Chapter 3 | 0 |
| Chapter 4 | -66.66% |
The number of heroes introduced in Chapter Five is 11.11% more than those introduced in Chapter Four. Furthermore, the ratio of total characters (heroes + villains) introduced in Chapter Five to Chapter Three is 7:6. Determine the number of villains introduced in Chapter Five.
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 5 Detailed Solution
General Solution:
We are given percentage distribution of total characters in each chapter as:
Chapter 1 = p/2%
Chapter 2 = 2p%
Chapter 3 = 3p%
Chapter 4 = 5(p − 1)%
Add all percentages to get total = 100%
⇒ p/2 + 2p + 3p + 5(p − 1) = 100
⇒ (p/2 + 2p + 3p + 5p − 5) = 100
⇒ (10.5p − 5) = 100
⇒ 10.5p = 105
⇒ p = 10
Now find % of total characters per chapter:
Chapter 1 = p/2 = 10/2 = 5%
Chapter 2 = 2p = 20%
Chapter 3 = 3p = 30%
Chapter 4 = 5(p − 1) = 5 × 9 = 45%
Given: In Chapter 1, 5 heroes were introduced
If heroes = 5 and heroes are 66.66% more than villains:
⇒ Let villains = x ⇒ 5 = x + (66.66% of x) = x + (2/3)x = (5/3)x
⇒ x = 3 ⇒ Villains = 3
⇒ Total characters in Chapter 1 = 5 + 3 = 8
Since 5% = 8 characters ⇒ Total characters = 8 ÷ 0.05 = 160
Characters per chapter
Chapter 1 = 5% of 160 = 8 (Already known: Heroes = 5, Villains = 3)
Chapter 2 = 20% of 160 = 32
Chapter 3 = 30% of 160 = 48
Chapter 4 = 45% of 160 = 72
Chapter 2: Heroes are 40% LESS than villains
Let villains = x ⇒ heroes = x − 40% of x = 0.6x
Total = x + 0.6x = 1.6x = 32
⇒ x = 32 ÷ 1.6 = 20 ⇒ Heroes = 0.6 × 20 = 12
Chapter 2: Heroes = 12, Villains = 20
Chapter 3: Heroes = Villains
Total = 48 ⇒ Heroes = 24, Villains = 24
Chapter 4: Heroes are 66.66% LESS than villains
⇒ Heroes = x, Villains = x + 66.66% of x = x + (2/3)x = (5/3)x
Total = x + (5/3)x = (8/3)x = 72
⇒ x = 72 × (3 ÷ 8) = 27
⇒ Villains = 72 − 27 = 45
Chapter 4: Heroes = 27, Villains = 45
Thus,
| Chapter | Heroes | Villains | Total |
|---|---|---|---|
| Chapter 1 | 5 | 3 | 8 |
| Chapter 2 | 12 | 20 | 32 |
| Chapter 3 | 24 | 24 | 48 |
| Chapter 4 | 27 | 45 | 72 |
Total characters introduced = 160
Calculations:
Given:
Heroes in Chapter 4 = 27
Heroes in Chapter 5 = 11.11% more than 27
Total characters in Chapter 3 = 48
Ratio of total characters in Chapter 5 to Chapter 3 = 7 : 6
Find Heroes in Chapter 5
11.11% more than 27 = 27 + (11.11% of 27)
⇒ 11.11% = 1/9 ⇒ Increase = 27 ÷ 9 = 3
⇒ Heroes in Chapter 5 = 27 + 3 = 30
Use ratio of total characters (Ch5 : Ch3 = 7 : 6):
Total in Chapter 3 = 48
⇒ Total in Chapter 5 = (7/6) × 48 = 56
Villains in Chapter 5 = Total − Heroes
⇒ Villains = 56 − 30 = 26
Thus, the correct answer is 26 villains.
Top Tabulation and Pie Chart MCQ Objective Questions
The given pie chart shows the percentage of students in five schools and the table shows the ratio of boys and girls in each school.
Study the pie chart and table and answer the question that follows.
The below table shows the ratio of girls and boys in the given five schools.
|
School |
Girls : Boys |
|
A |
3 ∶ 4 |
|
B |
2 ∶ 3 |
|
C |
5 ∶ 3 |
|
D |
1 ∶ 2 |
|
E |
4 ∶ 1 |
If the total number of girls from all five schools is represented as a pie chart, then what will be the measure of the sector angle (to the nearest integer) corresponding to school B?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 6 Detailed Solution
Download Solution PDFGiven:
There is the percentage of students in five schools in the given pie chart and the table shows the ratio of boys and girls in each school.
Concept used:
The total angle of a pie chart = 360°
Calculation:
Let, the total number of students = 100
So, the total students of each schools are:
A = 28; B = 15; C = 24; D = 18; E = 15
Then, the total number of girl student in school B = (2/5) × 15 = 6
The total number of girl student in all schools = [(3/7) × 28 + (2/5) × 15 + (5/8) × 24 + (1/3) × 18 + (4/5) × 15]
= 12 + 6 + 15 + 6 + 12
= 51
The angle =
⇒ (6/51) × 360 = 42.35...° ≈ 42° (the nearest integer)
∴ The measure of the sector angle (to the nearest integer) will be 42°
Study the given data and answer the question that follows. Data regarding population of different states in the year 2015 is shown in the pie-chart and table.
| States | Sex and Literacy-wise Population Ratio | |||
| Sex | Literacy | |||
| M | F | Literate | Illiterate | |
| A.P | 5 | 3 | 2 | 7 |
| M.P | 3 | 1 | 1 | 4 |
| Delhi | 2 | 3 | 2 | 1 |
| Goa | 3 | 5 | 3 | 2 |
| Bihar | 3 | 4 | 4 | 1 |
| U.P. | 3 | 2 | 7 | 2 |
| T.N. | 3 | 4 | 9 | 4 |
If the total population of the given states is 31,5000, then what was the total number of illiterate people in Goa and M.P.?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 7 Detailed Solution
Download Solution PDFCalculation:
The number of illiterate people in Goa is , 2/5 × 315000 × 12/100 =15120
The number of illiterate people in MP is , 4/5 × 315000 × 20/100 =50400
Total is 50400 + 15120 = 65520
∴ The correct option is 1
Study the given graph and table and answer the following question. Data of different states regarding population of states in the year 1998
Total population of the given states = 32760000
|
States |
Sex literacy wise Population Ratio |
|||
|
Sex |
Literacy |
|||
|
M |
F |
Literate |
Illiterate |
|
|
Arunachal Pradesh |
5 |
3 |
2 |
7 |
|
Madhya Pradesh |
3 |
1 |
1 |
4 |
|
Delhi |
2 |
3 |
2 |
1 |
|
Goa |
3 |
5 |
3 |
2 |
|
Bihar |
3 |
4 |
4 |
1 |
|
Uttar Pradesh |
3 |
2 |
7 |
2 |
|
Tamil Nadu |
3 |
4 |
9 |
4 |
If in the year 1998, there was an increase of 20% in the population of Goa and 10% in the population of Arunachal Pradesh compared to the previous year, then what was the ratio of populations of Goa and Arunachal Pradesh in 1997?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 8 Detailed Solution
Download Solution PDFCalculation:
Population of Goa in the year 1998 = 32760000 × 12%
⇒ 39,31,200
Population of Goa in the year 1997 = 39,31,200 × 100/120
⇒ 32,76,000
Population of Arunachal Pradesh in the year 1998 = 32760000 × 25%
⇒ 81,90,000
Population of Arunachal Pradesh in the year 1997 = 81,90,000 × 100/110
⇒ 81,90,0000/11
Ratio = 3276000 : 81,90,0000/11
⇒ 11 : 25
∴ The required answer is 11 : 25.
Study the given graph and table and answer the following question.
Data of different states regarding population of states in the year 1998
Total population of the given states = 32760000
| States | Sex and literacy wise Population Ratio | |||
| Sex | Literacy | |||
| M | F | Literate | Illiterate | |
| Arunachal Pradesh | 5 | 3 | 2 | 7 |
| Madhya Pradesh | 3 | 1 | 1 | 4 |
| Delhi | 2 | 3 | 2 | 1 |
| Goa | 3 | 5 | 3 | 2 |
| Bihar | 3 | 4 | 4 | 1 |
| Uttar Pradesh | 3 | 2 | 7 | 2 |
| Tamil Nadu | 3 | 4 | 9 | 4 |
What was the ratio of the number of females in Arunachal Pradesh to the number of females in Uttar Pradesh?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 9 Detailed Solution
Download Solution PDFGiven:
Total population of the given states = 32760000
Calculation:
Total percentage as per the pie chart is 100%
⇒ 100% = 32760000
⇒ 1% = 327600
As per the question,
The population of Arunachal Pradesh,
⇒ 25 × 327600
The population of Uttar Pradesh,
⇒ 15 × 327600
Now female in Arunachal Pradesh is 3/8
and female in Uttar Pradesh is 2/5
⇒ 25 × 327600 × 3/8 = 15 × 327600 × 2/5
⇒ 25:16
∴ The ratio of the number of females in Arunachal Pradesh to the number of females in Uttar Pradesh was 25 ∶ 16.
Answer the question given below on the basis of the following table.
|
If the data regarding vacant seats for first class AC category is represented by a pie-chart, then the central angle of the area representing vacant seats for first class AC class on Thursday will be:
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 10 Detailed Solution
Download Solution PDFGiven:
In 150 seats, the occupied seats for First class AC class on Monday = 145
In 150 seats, the occupied seats for First class AC class on Tuesday = 120
In 150 seats, the occupied seats for First class AC class on Wednesday = 130
In 150 seats, the occupied seats for First class AC class on Thursday = 125
In 150 seats, the occupied seats for First class AC class on Friday = 130
Calculation:
According to the question,
The total vacant seats for First class AC class from Monday to Friday:
⇒ (150 – 145) + (150 – 120) + (150 – 130) + (150 – 125) + (150 – 130)
⇒ 5 + 30 + 20 + 25 + 20 = 100
Vacant seats for first class AC class on Thursday = 150 - 125 = 25
As per the concept used:
100 → 360°
⇒ 25 → (360° × 25)/100
⇒ 25 → 90°
∴ Option (1) is the correct answerStudy the given graph and table and answer the following question.
Data of different states regarding population of states in the year 1998
Total population of the given states = 32760000
| State | Sex and literacy wise Population Ratio | |||
| Sex | Literacy | |||
| M | F | Literate | Illiterate | |
| Arunachal Pradesh | 5 | 3 | 2 | 7 |
| Madhya Pradesh | 3 | 1 | 1 | 4 |
| Delhi | 2 | 3 | 2 | 1 |
| Goa | 3 | 5 | 3 | 2 |
| Bihar | 3 | 4 | 4 | 1 |
| Uttar Pradesh | 3 | 2 | 7 | 2 |
| Telangana | 3 | 4 | 9 | 4 |
What was the number of males in Bihar in the year 1998?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 11 Detailed Solution
Download Solution PDFCalculation:
Now, the number of males in Bihar in the year 1998
⇒ 32760000 × 11% × 3/(3 + 4)
⇒ 1544400
∴ The number of males in Bihar in the year 1998 is 15,44,400.
The following Pie chart represents the percentage-wise distribution of 300 students of class X in a school in six different sections A, B, C, D, E and F.
The table given below shows the number of boys of class X in six different sections A, B, C, D, E and F.
| Section | A | B | C | D | E | F |
| No. of boys | 36 | 26 | 34 | 28 | x | 20 |
If in section E, the ratio of the number of boys to the number of girls is 3 : 4, then the ratio of number of boys in section E to the number of girls in section C is:
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 12 Detailed Solution
Download Solution PDFCalculation:
Total number of students in section E = 300 × 14/100 = 42
Number of boys in section E = 42 × 3/7 = 18
Total number of students in section C = 300 × 19/100 = 57
Number of girls in section C = 57 - 34 = 23
∴ the ratio of number of boys in section E to the number of girls in section C is = 18 : 23
Study the following pie chart and answer the following questions
Total number of students in five institutes = 3600
|
Ratio between boys and girls |
|
|
Institute |
Boys ∶ Girls |
|
A |
7 ∶ 5 |
|
B |
4 ∶ 5 |
|
C |
7 ∶ 11 |
|
D |
5 ∶ 4 |
|
E |
5 ∶ 7 |
The difference between the average number of girls in Institutes A, B and E and the number of boys in Institute D is x. The value of x lies between
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 13 Detailed Solution
Download Solution PDFCalculation:
Number of girls in institute A = 3600 × 18% × 5/(7 + 5) = 270
Number of girls in institute B = 3600 × 24% × 5/(4 + 5) = 480
Number of girls in institute E = 3600 × 16% × 7/(5 + 7) = 336
The average number of girls in Institutes A, B, and E = (270 + 480 + 336)/3 = 362
Number of boys in institute D = 3600 × 22% × 5/(5 + 4) = 440
Now, The difference between the average number of girls in Institutes A, B and E and the number of boys in Institute D
⇒ 440 - 362
⇒ 78 = x
∴ The value of x lies between 70 and 80.
The given pie chart shows the percentage of students in five schools and the table shows the ratio of boys and girls in each school.
Study the pie chart and table and answer the question that follows.
The below table shows the ratio of girls and boys in the given five schools.
| School | Girls ∶ Boys |
| A | 3 ∶ 4 |
| B | 2 ∶ 3 |
| C | 5 ∶ 3 |
| D | 1 ∶ 2 |
| E | 4 ∶ 1 |
The number of girls in school D is what percentage less than the number of boys in school B (correct to the nearest integer)?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 14 Detailed Solution
Download Solution PDFCalculation:
Let total number of students in the schools be 100
Number of students in school D = 100 × 18%
⇒ 18
Number of girls in school D = 18 × (1/3)
⇒ 6
Number of students in school B = 100 × 15%
⇒ 15
Number of boys in school B = 15 × (3/5)
⇒ 9
Difference = 9 - 6
⇒ 3
Required % = (3/9) × 100
⇒ 33.33% ≈ 33%
∴ Required answer is 33%.
This circle diagram shows the percentage distribution of total 800 employees in various departments of a company. The table shows the ratio of male and female employees in different departments.
|
Departments |
Male : Female |
|
HR |
3 : 5 |
|
IT |
2 : 3 |
|
Accounts |
3 : 7 |
|
Marketing |
7 : 4 |
|
Production |
5 : 3 |
What is the total number of male employees in the company?
Answer (Detailed Solution Below)
Tabulation and Pie Chart Question 15 Detailed Solution
Download Solution PDFTraditional method:
Employees in HR = 8% of 800 = 64
⇒ Number of males in HR = 3/8 × 64 = 24
Employees in IT = 15% of 800 = 120
⇒ Number of males in IT = 2/5 × 120 = 48
Employees in Accounts = 25% of 800 = 200
⇒ Number of males in Accounts = 3/10 × 200 = 60
Employees in Marketing = 22% of 800 = 176
⇒ Number of males in Marketing = 7/11 × 176 = 112
Employees in Production = 30% of 800 = 240
⇒ Number of males in Production = 5/8 × 240 = 150
∴ Total number of males = 24 + 48 + 60 + 112 + 150 = 394
Alternate Method
The percentage of male employees = 8 × 3/8 + 15 × 2/5 + 25 × 3/10 + 22 × 7/11 + 30 × 5/8
= 3 + 6 + 7.5 + 14 + 18.75
= 49.25%
- Total no. of males
= 49.25% of 800
= (800 × 49.25)/100
= 394