Riveted Connections MCQ Quiz - Objective Question with Answer for Riveted Connections - Download Free PDF
Last updated on Jun 16, 2025
Latest Riveted Connections MCQ Objective Questions
Riveted Connections Question 1:
The strength of a joint in a bolted connection is 620 kN. The size of plate is 180 mm width and 20 mm thick. If the yield strength of material of plate as 250 N/mm2 and partial safety factor as 1.1, then the efficiency of the joint is ______.
Answer (Detailed Solution Below)
Riveted Connections Question 1 Detailed Solution
Concept:
where, Ps = strength of joint in shear
Pb = strength of joint in bearing
Pt = strength of joint in tearing
P = strength of plate in tearing when no deduction has been made for rivet hole = p.t.ft
Calculation:
Given,
strength of joint in bolted connection = 620 kN
size of plate = (180 × 20) mm
yield strength of material = 250 MPa
FOS = 1.1
strength of plate =
efficiency ( η ) = (620/818.18) × 100 = 75.77%
Riveted Connections Question 2:
As per IS 800, the minimum pitch of rivets in a row is recommended as:
Answer (Detailed Solution Below)
Riveted Connections Question 2 Detailed Solution
Explanation
Specifications of Pitch of rivet:
- Pitch is the distance between two adjacent rows of rivet parallel to the direction of application of force. The minimum pitch will be 2.5 times the gross diameter.
- The minimum pitch should not be less than 2.5 times the nominal diameter of the rivet.
- As a thumb rule pitch equal to 3 times the nominal diameter of the rivet is adopted.
For Maximum pitch:
The maximum pitch of bolts or rivets or welds in the compression zone
The maximum pitch of bolts or rivets or welds in the tension zone
Riveted Connections Question 3:
Calculate the value of minimum edge distance for 20 mm diameter bolt using machine flame cut.
Answer (Detailed Solution Below)
Riveted Connections Question 3 Detailed Solution
Concept:
Specification for the pitch of bolts or rivets
1. Minimum pitch and minimum gauge length
- P = 2.5 × nominal diameter of the bolt
2. Minimum end and edge distance
- emin = 1.5 × diameter of the bolt hole ....... (for machine cut element)
- emin = 1.7 × diameter of the bolt hole ....... (for hand-cut element)
Calculation:
Given,
Diameter of bolt = 20 mm,
as the bolt diameter is in the range of (16 - 24) mm
Hole Dia = Bolt dia + 2 mm = 20 + 2 = 22 mm
Minimum edge Distance for machine flame cut = 1.5 × 22 = 33 mm
Additional Information
3. Maximum end and edge distance
- emax = 12 × t × ϵ
- Where, ϵ
, fy = yield stress and t = thickness of thinner plate.
4. The maximum pitch of bolts or rivets or welds in the compression zone
Pmax = minimum { 12 × t or 200 mm } ....... (For compression zone)
Where, t = thickness of the thinner plate
5. The maximum pitch of bolts or rivets or welds in the tension zone
Pmax = minimum { 16 × t or 200 mm } ....... (For tension zone)
Where, t = thickness of the thinner plate
Riveted Connections Question 4:
For field rivets the maximum permissible stresses in rivets and bolts as given in codes are reduced by:
Answer (Detailed Solution Below)
Riveted Connections Question 4 Detailed Solution
Explanation:
(i) As per IS 800:1984 Recommendations, Maximum permissible stress in rivets and bolts
Types of fastener |
Axial tension (Mpa) |
Shear (Mpa) |
Bearing (Mpa) |
(i) Power-driven Shop rive Field Rivet |
100 90 |
100 90 |
300 270 |
(ii) Hand driven rivets |
80 |
80 |
250 |
(iii) Closed tolerance and turned bolts |
120 |
100 |
300 |
(iv) Bolt in clearance holes |
120 |
80 |
250 |
So from the table, it is clear that For field rivets the maximum permissible stresses in rivets and bolts as given in codes are reduced by 10%.
Riveted Connections Question 5:
The partial safety factor for a material of bolts is
Answer (Detailed Solution Below)
Riveted Connections Question 5 Detailed Solution
Explanation:
Partial Safety Factor for Bolts
The partial safety factor is a parameter used in design to account for uncertainties in material properties, manufacturing processes, and applied loads. It ensures a margin of safety in the design process. For bolts, the partial safety factor is determined based on codes and standards to ensure their reliability under various conditions.
Analyzing the Given Options
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"Option 1: 1" (Incorrect)
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A partial safety factor of 1 would imply no additional safety margin, which is not acceptable in engineering design as it doesn’t account for uncertainties.
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"Option 2: 1.1" (Incorrect)
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A value of 1.1 is too low for bolts, considering the uncertainties in material properties and the stress they endure during loading.
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"Option 3: 1.15" (Incorrect)
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While 1.15 is a commonly used safety factor for certain materials, it is not the standard for bolts as per codes and standards.
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"Option 4: 1.25" (Correct)
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A partial safety factor of 1.25 is widely accepted for bolts in structural design, ensuring adequate safety against uncertainties in material strength and load application.
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"Option 5: Not provided" (Not Applicable)
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This option is invalid as it does not specify any value for the partial safety factor.
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Top Riveted Connections MCQ Objective Questions
When the effect of wind or earthquake load is taken into account, the permissible stress as specified in rivets may be increased by
Answer (Detailed Solution Below)
Riveted Connections Question 6 Detailed Solution
Download Solution PDFConcept:
According to clause no. 11.1.4 of IS 800: 2007, when the effect of wind or earthquake load is taken into account, the permissible stress as specified in rivets (or in anchor bolts) may be increased by 25%.
Confusion/Mistake Point:
According to clause no. 11.1.4 of IS 800: 2007, when the effect of wind or earthquake load is taken into account, the permissible stress as specified in structural steel member may be increased by 33.33%.
As per IS 800, the efficiency of a riveted joint having the minimum pitch is:
Answer (Detailed Solution Below)
Riveted Connections Question 7 Detailed Solution
Download Solution PDFConcept:
Tensile Stresses in the main plates might result in tearing of the main plate or cover plate across a row of the bolt.
The resistance offered by the plate against tearing is known as the tearing strength or tearing value of the plate.
Tearing efficiency of joints is given by,
Calculation:
Given, Minimum pitch of rivet joint(p) = 2.5d
Which of the following statement is INCORRECT about the design of riveted joints?
Answer (Detailed Solution Below)
Riveted Connections Question 8 Detailed Solution
Download Solution PDFExplanation:
Assumptions in the design of riveted joints:
- The friction among the plates is neglected.
- Shear stress across a cross-section of a rivet is uniform.
- The bearing stress distribution on the plate cross-section between rivet holes is uniform.
- All rivets within a riveting group subjected to a direct load passing through their CG share the load equally.
- Rivet shanks and after driving, fill the rivet holes completely.
- The tensile stress is uniform in the section of metal between the rivets.
Rivets under combined stresses must be subjected to a limit as Where, τv and σt = The actual shear and tensile stresses in the rivets, respectively. τvf and σtf = Allowable shear and tensile stresses in the rivets, respectively.
Answer (Detailed Solution Below)
Riveted Connections Question 9 Detailed Solution
Download Solution PDFConcept-
As per IS code-
Rivets under combined stresses must be subjected to a limit as
Where, τv and σt = The actual shear and tensile stresses in the rivets, respectively.
τvf and σtf = Allowable shear and tensile stresses in the rivets, respectively.
As per IS 800:2007 clause no 10.3.6
A bolt required to resist both design shear force (Vsb) and design tensile force (Tb) at the same time shall satisfy:
Where Vsb = factored shear force acting on the bolt
vdb = design shear capacity
Tb = factored tensile force acting on the bolt
Tdb = design tension capacity
The maximum design force for a rivet in the following bracket connection, if the spacing between adjacent rivets is 150 mm, is
Answer (Detailed Solution Below)
Riveted Connections Question 10 Detailed Solution
Download Solution PDFConcept:
The maximum resultant shear force between F1 and F2 is FR given by,
Where,
F1 = shear force in any rivet due to direct load ‘P’
F2 = shear force in rivet due to twisting moment M
r = radial distance of rivet from C.G of rivet group
The critical rivet is the one for which r is maximum and θ is minimum
Calculation:
P= 450 kN
n = 5
F1 = 90 kN
F2 = 120 kN
θ = 0°
FR = 210 kN
Which of the following is the main advantage of rivets in steel construction?
Answer (Detailed Solution Below)
Riveted Connections Question 11 Detailed Solution
Download Solution PDFConcepts:
A rivet has a cylindrical shank with a head at one end. It is used to make permanent joints between two plates. Rivet is inserted into the holes of plates (which are to be joined) and then its protruding part is upset by a hammer.
Advantages of Rivet connection:
- It is more reliable
- It can also be used for non ferrous metals
- Parts assembled by Riveted joint do not have any thermal after effec
- Its quality inspection is easy and cheap
- When parts are dismantled riveted parts have less damage compared to welded parts
- They have good vibration damping capabilities so where required rivets are used in place of it
Disadvantages of Riveted joints
- Due to holes plates become weak.
- Labor cost is more as more and skilled workforce is needed.
- Overall cost of riveted joints is more.
- They have more weight than welded joints.
- Riveting process creates more noise.
- Stress concentration near holes.
For 20 mm diameter rivet, the diameter of rivet hole is
Answer (Detailed Solution Below)
Riveted Connections Question 12 Detailed Solution
Download Solution PDFConcept:
Gross diameter is the diameter of rivet when it is fully inserted in the rivet hole or body. This diameter is more than the diameter of shank (when it is cold or before insertion i.e. nominal diameter)
Important points:
Due to the heating effect, the size of rivets gets expanded which upon cooling gets reduced (called shank diameter).
Rivet hole diameter is calculated as:
Rivet size, d (in mm) |
Rivet hole size, do (in mm) |
d ≤ 25mm |
d + 1.5mm |
d > 25mm |
d + 2mm |
Calculation:
d = 20 + 1.5 = 21.5 mm
The given figure shows:
Answer (Detailed Solution Below)
Riveted Connections Question 13 Detailed Solution
Download Solution PDFExplanation:
In double cover butt joint, the bolts or rivets can be placed in the following manner:
1. In multiple rows having zero staggered pitch called chain riveting as shown in the following figure:
2. In multiple rows having either non-uniform pitch or having staggered pitch i.e. bolts are placed in a zig-zag pattern as shown below:
Additional Information
As per IS 800:2007, the tensile strength based on rupture of the net section of the plate is given as:
Where,
fu = Ultimate strength of the plate
Anet = Minimum net area of the section
γ = Factor of safety for plate
To calculate Anet, all possible failure paths (straight as well as zig-zag) are required to be considered and the corresponding net area is to be computed for each possible failure path and the minimum net area is to be selected.
Where,
t is the thickness of the plate joined.
dh is the diameter of the hole
s is staggered pitch , g is gauge distance, b is width of plate
If the working stress in bearing in power driven rivets is 300 N/mm2 and a double riveted double cover butt joint is used to connect plates of 12 mm thick, then the strength of rivet in bearing is
(Given: The nominal diameter of rivet = 22 mm)
Answer (Detailed Solution Below)
Riveted Connections Question 14 Detailed Solution
Download Solution PDFConcept:
Strength of rivet in bearing (Pb)
Where σb = Permissible bearing stress in rivet.
Pb = Bearing strength of rivet.
d' = Gross diameter of rivet or dia of hole.
Calculation:
Given
Bearing stress (
Nominal diameter of rivet (d) = 22 mm
Gross diameter of rivet (d') = 22 + 1.5 = 23.5 mm
Thickness of plate (t) = 12 mm
Bearing strength of rivet (Pb) = 300 × 23.5 × 12 = 84600 N
Bearing strength of rivet (Pb) = 84.6 kN
In riveted connection, the allowance (increase) that is to be provided to the nominal diameter of rivets having diameter greater than 25 mm, so as to work out the gross diameter is:
Answer (Detailed Solution Below)
Riveted Connections Question 15 Detailed Solution
Download Solution PDFExplanation:
Gross diameter = Nominal diameter + 1.5 mm, ϕ ≤ 25 mm
Gross diameter = Nominal diameter + 2 mm, ϕ > 25 mm
ϕ = Nominal diameter
Additional Information As per the IS 800 – 2007, the minimum pitch that should be maintained is 2.5 times the nominal diameter of the bolt and
the minimum end distance that should be maintained is 1.5 times the hole diameter.
The hole diameter is to be calculated based on the following table:
Nominal diameter |
Hole size |
12 - 14 mm |
1 mm extra |
16 - 24 mm |
2 mm extra |
> 24 mm |
3 mm extra |