Memory Address Map MCQ Quiz - Objective Question with Answer for Memory Address Map - Download Free PDF

Explanation:

1. Understanding the Memory Size:

The size of the RAM is specified as 2K × 8 bits. This means the RAM has 2K memory locations, where each location can store 8 bits (1 byte) of data. The total number of memory addresses in this RAM is:

2K = 2 × 1024 = 2048 addresses.

2. Starting Address:

The RAM's starting address is CC00 (in hexadecimal format).

3. Calculating the Last Address:

To determine the last address, we add the total number of addresses (2048) to the starting address (CC00) and subtract 1. This subtraction is necessary because the starting address is inclusive, meaning the first address itself counts as one of the 2048 addresses.

Last Address = Starting Address + (Total Addresses - 1)

Last Address = CC00 + (2048 - 1)

Last Address = CC00 + 2047

4. Hexadecimal Addition:

To add CC00 and 2047 in hexadecimal format:

• Convert 2047 to hexadecimal: 2047 (decimal) = 07FF (hexadecimal).
• Add CC00 (starting address) and 07FF (hexadecimal representation of 2047).

CC00 + 07FF = D3FF

Therefore, the last address of the byte in this RAM is D3FF.

Correct Answer: Option 3 (D3FF)

 The correct answer is Oxford architecture.

Key Points

• The Oxford architecture is not classified as a type of computer architecture. 
• Harvard architecture: This type of architecture uses separate memory and separate buses for instructions and data. It is commonly found in microcontrollers and digital signal processors (DSPs). The Harvard architecture is distinct from the Von Neumann architecture (which combines instructions and data in a single memory).
• Micro architecture: Also known as computer organization, this refers to the internal design and implementation of a specific processor or computer system. It includes details such as the instruction set, pipelines, caches, and control units. Micro architecture is essential for achieving high performance and efficiency.
• Von Neumann architecture: Named after mathematician and computer scientist John von Neumann, this architecture is the foundation for most modern computers. It features a single memory that holds both instructions and data. The Von Neumann architecture is characterized by its fetch-decode-execute cycle.
• In summary, Oxford architecture is not a recognized type of computer architecture.
• The other three options—Harvard architecture, micro architecture, and Von Neumann architecture—are well-established concepts in the field of computer science

• Memory-mapped I/O uses the same address space to address both memory and I/O devices.
• The memory and registers of the I/O devices are mapped to (associated with) address values.
• So when an address is accessed by the CPU, it may refer to a portion of physical RAM, or it can instead refer to the memory of the I/O device.

Thus, the CPU instructions used to access the memory can also be used for accessing devices

Specification of RAM = 4K × 8 bit

Size of the RAM = 2² × 2¹⁰ × 8 bit

= 2¹² × 8 bit

So 12 address lines will be engaged.

Number of address locations = 0FFFH

Starting address = AA00H

So, final address = (AA00H + 0FFFH) = B9FFH

Key Points

The correct answer is option 4 i.e RAM and I/O.

• DMA stands for Direct Memory Access in computers.
  • Direct memory access (DMA) is a method of transferring data from the computer's RAM to Input/Output devices of the computer without processing it using the CPU.
  • In order for devices to use direct memory access, they must be assigned to a DMA channel.
  • DMA is also used for "memory to memory" copying or moving of data within memory.
  • A DMA channel enables a device to transfer data without exposing the CPU to a work overload.

Types of DMA transfer using a DMA controller:

• Burst or Block Transfer DMA
• Cycle Stealing or Single-Byte Transfer
• Transparent or Hidden DMA Transfer

Specification of RAM = 4K × 8 bit

Size of the RAM = 2² × 2¹⁰ × 8 bit

= 2¹² × 8 bit

So 12 address lines will be engaged.

Number of address locations = 0FFFH

Starting address = AA00H

So, final address = (AA00H + 0FFFH) = B9FFH

• Memory-mapped I/O uses the same address space to address both memory and I/O devices.
• The memory and registers of the I/O devices are mapped to (associated with) address values.
• So when an address is accessed by the CPU, it may refer to a portion of physical RAM, or it can instead refer to the memory of the I/O device.

Thus, the CPU instructions used to access the memory can also be used for accessing devices

Explanation:

1. Understanding the Memory Size:

The size of the RAM is specified as 2K × 8 bits. This means the RAM has 2K memory locations, where each location can store 8 bits (1 byte) of data. The total number of memory addresses in this RAM is:

2K = 2 × 1024 = 2048 addresses.

2. Starting Address:

The RAM's starting address is CC00 (in hexadecimal format).

3. Calculating the Last Address:

To determine the last address, we add the total number of addresses (2048) to the starting address (CC00) and subtract 1. This subtraction is necessary because the starting address is inclusive, meaning the first address itself counts as one of the 2048 addresses.

Last Address = Starting Address + (Total Addresses - 1)

Last Address = CC00 + (2048 - 1)

Last Address = CC00 + 2047

4. Hexadecimal Addition:

To add CC00 and 2047 in hexadecimal format:

• Convert 2047 to hexadecimal: 2047 (decimal) = 07FF (hexadecimal).
• Add CC00 (starting address) and 07FF (hexadecimal representation of 2047).

CC00 + 07FF = D3FF

Therefore, the last address of the byte in this RAM is D3FF.

Correct Answer: Option 3 (D3FF)

Key Points

The correct answer is option 4 i.e RAM and I/O.

• DMA stands for Direct Memory Access in computers.
  • Direct memory access (DMA) is a method of transferring data from the computer's RAM to Input/Output devices of the computer without processing it using the CPU.
  • In order for devices to use direct memory access, they must be assigned to a DMA channel.
  • DMA is also used for "memory to memory" copying or moving of data within memory.
  • A DMA channel enables a device to transfer data without exposing the CPU to a work overload.

Types of DMA transfer using a DMA controller:

• Burst or Block Transfer DMA
• Cycle Stealing or Single-Byte Transfer
• Transparent or Hidden DMA Transfer

Specification of RAM = 4K × 8 bit

Size of the RAM = 2² × 2¹⁰ × 8 bit

= 2¹² × 8 bit

So 12 address lines will be engaged.

Number of address locations = 0FFFH

Starting address = AA00H

So, final address = (AA00H + 0FFFH) = B9FFH

Opcode(4)+Address(6)+Address(6)=16 bit

N=16

No of free opcodes=16-2=14

Number of one address instruction=14x64=896

Free opcodes=896-60=836

Number of zero address instruction=836x64=53,504

• Memory-mapped I/O uses the same address space to address both memory and I/O devices.
• The memory and registers of the I/O devices are mapped to (associated with) address values.
• So when an address is accessed by the CPU, it may refer to a portion of physical RAM, or it can instead refer to the memory of the I/O device.

Thus, the CPU instructions used to access the memory can also be used for accessing devices

Explanation:

1. Understanding the Memory Size:

The size of the RAM is specified as 2K × 8 bits. This means the RAM has 2K memory locations, where each location can store 8 bits (1 byte) of data. The total number of memory addresses in this RAM is:

2K = 2 × 1024 = 2048 addresses.

2. Starting Address:

The RAM's starting address is CC00 (in hexadecimal format).

3. Calculating the Last Address:

To determine the last address, we add the total number of addresses (2048) to the starting address (CC00) and subtract 1. This subtraction is necessary because the starting address is inclusive, meaning the first address itself counts as one of the 2048 addresses.

Last Address = Starting Address + (Total Addresses - 1)

Last Address = CC00 + (2048 - 1)

Last Address = CC00 + 2047

4. Hexadecimal Addition:

To add CC00 and 2047 in hexadecimal format:

• Convert 2047 to hexadecimal: 2047 (decimal) = 07FF (hexadecimal).
• Add CC00 (starting address) and 07FF (hexadecimal representation of 2047).

CC00 + 07FF = D3FF

Therefore, the last address of the byte in this RAM is D3FF.

Correct Answer: Option 3 (D3FF)

 The correct answer is Oxford architecture.

Key Points

• The Oxford architecture is not classified as a type of computer architecture. 
• Harvard architecture: This type of architecture uses separate memory and separate buses for instructions and data. It is commonly found in microcontrollers and digital signal processors (DSPs). The Harvard architecture is distinct from the Von Neumann architecture (which combines instructions and data in a single memory).
• Micro architecture: Also known as computer organization, this refers to the internal design and implementation of a specific processor or computer system. It includes details such as the instruction set, pipelines, caches, and control units. Micro architecture is essential for achieving high performance and efficiency.
• Von Neumann architecture: Named after mathematician and computer scientist John von Neumann, this architecture is the foundation for most modern computers. It features a single memory that holds both instructions and data. The Von Neumann architecture is characterized by its fetch-decode-execute cycle.
• In summary, Oxford architecture is not a recognized type of computer architecture.
• The other three options—Harvard architecture, micro architecture, and Von Neumann architecture—are well-established concepts in the field of computer science

Option 1: False

Memory Management uses BitMap and linked list to keep track of dynamically allocated memory

Option 2: False

An address seen by the memory unit is commonly referred to as the physical address, that is, Memory is accessed using the physical address. 

Option 3: True

The memory management unit (MMU) translates a logical or virtual address to a physical address.

Option 4: False

An address generated by the CPU is commonly referred to as a logical address.