Line Graph MCQ Quiz - Objective Question with Answer for Line Graph - Download Free PDF
Last updated on Jun 23, 2025
Latest Line Graph MCQ Objective Questions
Line Graph Question 1:
Comprehension:
Directions: Study the information carefully and answer the questions.
The line graph shows the total number of firefighters in five districts (A, B, C, D, E). It also shows the difference between full-time and volunteer firefighters (full-time > volunteer). The total number of firefighters across all districts is 4,200.
If the total firefighters in A and Y is 1500, find the difference between firefighters in Y and full-time in B.
Answer (Detailed Solution Below)
Line Graph Question 1 Detailed Solution
General Solution:
Given: Total number of firefighters across all districts = 4200
Let the total number of firefighters in terms of x be:
District A = 6x
District B = 7.2x
District C = 9x
District D = 9.6x
District E = 10.2x
Add total firefighters across all districts:
6x + 7.2x + 9x + 9.6x + 10.2x = 42x
⇒ 42x = 4200
⇒ x = 4200 ÷ 42 = 100
Calculate total firefighters in each district using x = 100:
District A = 6 × 100 = 600
District B = 7.2 × 100 = 720
District C = 9 × 100 = 900
District D = 9.6 × 100 = 960
District E = 10.2 × 100 = 1020
Use difference between full-time and volunteer firefighters:
District A: Total = 600, Difference = 288
⇒ Let volunteer = a, then full-time = a + 288
⇒ a + (a + 288) = 600 ⇒ 2a + 288 = 600
⇒ 2a = 312 ⇒ a = 156
⇒ Volunteer = 156, Full-time = 444
District B: Total = 720, Difference = 120
⇒ Let volunteer = a, full-time = a + 120
⇒ 2a + 120 = 720 ⇒ 2a = 600 ⇒ a = 300
⇒ Volunteer = 300, Full-time = 420
District C: Total = 900, Difference = 180
⇒ Let volunteer = a, full-time = a + 180
⇒ 2a + 180 = 900 ⇒ 2a = 720 ⇒ a = 360
⇒ Volunteer = 360, Full-time = 540
District D: Total = 960, Difference = 336
⇒ Let volunteer = a, full-time = a + 336
⇒ 2a + 336 = 960 ⇒ 2a = 624 ⇒ a = 312
⇒ Volunteer = 312, Full-time = 648
District E: Total = 1020, Difference = 60
⇒ Let volunteer = a, full-time = a + 60
⇒ 2a + 60 = 1020 ⇒ 2a = 960 ⇒ a = 480
⇒ Volunteer = 480, Full-time = 540
Thus,
| District | Total | Full-time | Volunteer |
|---|---|---|---|
| A | 600 | 444 | 156 |
| B | 720 | 420 | 300 |
| C | 900 | 540 | 360 |
| D | 960 | 648 | 312 |
| E | 1020 | 540 | 480 |
Calculations:
Given:
Total firefighters in District A = 600
Total firefighters in District A + District Y = 1500
Find total firefighters in District Y:
⇒ Y = 1500 - 600 = 900
Full-time firefighters in District B = 420 (from general solution)
Find the difference:
⇒ Difference = Firefighters in Y - Full-time in B
⇒ Difference = 900 - 420 = 480
Thus, the correct answer: 480
Line Graph Question 2:
Comprehension:
Directions: Study the information carefully and answer the questions.
The line graph shows the total number of firefighters in five districts (A, B, C, D, E). It also shows the difference between full-time and volunteer firefighters (full-time > volunteer). The total number of firefighters across all districts is 4,200.
In district E, 80% firefighters are rural, and the rest urban. If the ratio of full-time to volunteer urban firefighters is 5:7, find full-time rural firefighters.
Answer (Detailed Solution Below)
Line Graph Question 2 Detailed Solution
General Solution:
Given: Total number of firefighters across all districts = 4200
Let the total number of firefighters in terms of x be:
District A = 6x
District B = 7.2x
District C = 9x
District D = 9.6x
District E = 10.2x
Add total firefighters across all districts:
6x + 7.2x + 9x + 9.6x + 10.2x = 42x
⇒ 42x = 4200
⇒ x = 4200 ÷ 42 = 100
Calculate total firefighters in each district using x = 100:
District A = 6 × 100 = 600
District B = 7.2 × 100 = 720
District C = 9 × 100 = 900
District D = 9.6 × 100 = 960
District E = 10.2 × 100 = 1020
Use difference between full-time and volunteer firefighters:
District A: Total = 600, Difference = 288
⇒ Let volunteer = a, then full-time = a + 288
⇒ a + (a + 288) = 600 ⇒ 2a + 288 = 600
⇒ 2a = 312 ⇒ a = 156
⇒ Volunteer = 156, Full-time = 444
District B: Total = 720, Difference = 120
⇒ Let volunteer = a, full-time = a + 120
⇒ 2a + 120 = 720 ⇒ 2a = 600 ⇒ a = 300
⇒ Volunteer = 300, Full-time = 420
District C: Total = 900, Difference = 180
⇒ Let volunteer = a, full-time = a + 180
⇒ 2a + 180 = 900 ⇒ 2a = 720 ⇒ a = 360
⇒ Volunteer = 360, Full-time = 540
District D: Total = 960, Difference = 336
⇒ Let volunteer = a, full-time = a + 336
⇒ 2a + 336 = 960 ⇒ 2a = 624 ⇒ a = 312
⇒ Volunteer = 312, Full-time = 648
District E: Total = 1020, Difference = 60
⇒ Let volunteer = a, full-time = a + 60
⇒ 2a + 60 = 1020 ⇒ 2a = 960 ⇒ a = 480
⇒ Volunteer = 480, Full-time = 540
Thus,
| District | Total | Full-time | Volunteer |
|---|---|---|---|
| A | 600 | 444 | 156 |
| B | 720 | 420 | 300 |
| C | 900 | 540 | 360 |
| D | 960 | 648 | 312 |
| E | 1020 | 540 | 480 |
Calculations:
Given for District E:
Total firefighters = 1020
Full-time = 540
Volunteer = 480
80% are rural ⇒ 80% of 1020 = (80/100) × 1020 = 816
Urban firefighters = 1020 - 816 = 204
Ratio of full-time to volunteer urban firefighters = 5 : 7
Let urban full-time = 5a and urban volunteer = 7a
⇒ 5a + 7a = 12a = 204 ⇒ a = 17
⇒ Urban full-time = 5 × 17 = 85
⇒ Urban volunteer = 7 × 17 = 119
Find rural firefighters:
Total full-time in E = 540
Urban full-time = 85
⇒ Rural full-time = 540 - 85 = 455
Thus, the correct answer: 455
Line Graph Question 3:
Comprehension:
Directions: Study the information carefully and answer the questions.
The line graph shows the total number of firefighters in five districts (A, B, C, D, E). It also shows the difference between full-time and volunteer firefighters (full-time > volunteer). The total number of firefighters across all districts is 4,200.
The number of full-time firefighters in B is what percentage of the total firefighters in C?
Answer (Detailed Solution Below)
Line Graph Question 3 Detailed Solution
General Solution:
Given: Total number of firefighters across all districts = 4200
Let the total number of firefighters in terms of x be:
District A = 6x
District B = 7.2x
District C = 9x
District D = 9.6x
District E = 10.2x
Add total firefighters across all districts:
6x + 7.2x + 9x + 9.6x + 10.2x = 42x
⇒ 42x = 4200
⇒ x = 4200 ÷ 42 = 100
Calculate total firefighters in each district using x = 100:
District A = 6 × 100 = 600
District B = 7.2 × 100 = 720
District C = 9 × 100 = 900
District D = 9.6 × 100 = 960
District E = 10.2 × 100 = 1020
Use difference between full-time and volunteer firefighters:
District A: Total = 600, Difference = 288
⇒ Let volunteer = a, then full-time = a + 288
⇒ a + (a + 288) = 600 ⇒ 2a + 288 = 600
⇒ 2a = 312 ⇒ a = 156
⇒ Volunteer = 156, Full-time = 444
District B: Total = 720, Difference = 120
⇒ Let volunteer = a, full-time = a + 120
⇒ 2a + 120 = 720 ⇒ 2a = 600 ⇒ a = 300
⇒ Volunteer = 300, Full-time = 420
District C: Total = 900, Difference = 180
⇒ Let volunteer = a, full-time = a + 180
⇒ 2a + 180 = 900 ⇒ 2a = 720 ⇒ a = 360
⇒ Volunteer = 360, Full-time = 540
District D: Total = 960, Difference = 336
⇒ Let volunteer = a, full-time = a + 336
⇒ 2a + 336 = 960 ⇒ 2a = 624 ⇒ a = 312
⇒ Volunteer = 312, Full-time = 648
District E: Total = 1020, Difference = 60
⇒ Let volunteer = a, full-time = a + 60
⇒ 2a + 60 = 1020 ⇒ 2a = 960 ⇒ a = 480
⇒ Volunteer = 480, Full-time = 540
Thus,
| District | Total | Full-time | Volunteer |
|---|---|---|---|
| A | 600 | 444 | 156 |
| B | 720 | 420 | 300 |
| C | 900 | 540 | 360 |
| D | 960 | 648 | 312 |
| E | 1020 | 540 | 480 |
Calculations:
Given:
Full-time firefighters in District B = 420
Total firefighters in District C = 900
Apply percentage formula:
Thus, the correct answer: 46.67%
Line Graph Question 4:
Comprehension:
Directions: Study the information carefully and answer the questions.
The line graph shows the total number of firefighters in five districts (A, B, C, D, E). It also shows the difference between full-time and volunteer firefighters (full-time > volunteer). The total number of firefighters across all districts is 4,200.
Find the ratio of volunteer firefighters in D to the total firefighters in A and E.
Answer (Detailed Solution Below)
Line Graph Question 4 Detailed Solution
General Solution:
Given: Total number of firefighters across all districts = 4200
Let the total number of firefighters in terms of x be:
District A = 6x
District B = 7.2x
District C = 9x
District D = 9.6x
District E = 10.2x
Add total firefighters across all districts:
6x + 7.2x + 9x + 9.6x + 10.2x = 42x
⇒ 42x = 4200
⇒ x = 4200 ÷ 42 = 100
Calculate total firefighters in each district using x = 100:
District A = 6 × 100 = 600
District B = 7.2 × 100 = 720
District C = 9 × 100 = 900
District D = 9.6 × 100 = 960
District E = 10.2 × 100 = 1020
Use difference between full-time and volunteer firefighters:
District A: Total = 600, Difference = 288
⇒ Let volunteer = a, then full-time = a + 288
⇒ a + (a + 288) = 600 ⇒ 2a + 288 = 600
⇒ 2a = 312 ⇒ a = 156
⇒ Volunteer = 156, Full-time = 444
District B: Total = 720, Difference = 120
⇒ Let volunteer = a, full-time = a + 120
⇒ 2a + 120 = 720 ⇒ 2a = 600 ⇒ a = 300
⇒ Volunteer = 300, Full-time = 420
District C: Total = 900, Difference = 180
⇒ Let volunteer = a, full-time = a + 180
⇒ 2a + 180 = 900 ⇒ 2a = 720 ⇒ a = 360
⇒ Volunteer = 360, Full-time = 540
District D: Total = 960, Difference = 336
⇒ Let volunteer = a, full-time = a + 336
⇒ 2a + 336 = 960 ⇒ 2a = 624 ⇒ a = 312
⇒ Volunteer = 312, Full-time = 648
District E: Total = 1020, Difference = 60
⇒ Let volunteer = a, full-time = a + 60
⇒ 2a + 60 = 1020 ⇒ 2a = 960 ⇒ a = 480
⇒ Volunteer = 480, Full-time = 540
Thus,
| District | Total | Full-time | Volunteer |
|---|---|---|---|
| A | 600 | 444 | 156 |
| B | 720 | 420 | 300 |
| C | 900 | 540 | 360 |
| D | 960 | 648 | 312 |
| E | 1020 | 540 | 480 |
Calculations:
Given:
Volunteer firefighters in District D = 312
Total firefighters in District A = 600
Total firefighters in District E = 1020
Total firefighters in A and E:
⇒ 600 + 1020 = 1620
Find the ratio:
Ratio = Volunteer in D : (Total in A + E)
⇒ 312 : 1620
⇒ Divide both by 12: (312 ÷ 12) : (1620 ÷ 12) = 26 : 135
Thus, the correct answer: 26 : 135
Line Graph Question 5:
Comprehension:
Directions: Study the information carefully and answer the questions.
The line graph shows the total number of firefighters in five districts (A, B, C, D, E). It also shows the difference between full-time and volunteer firefighters (full-time > volunteer). The total number of firefighters across all districts is 4,200.
If the average number of full-time firefighters in districts A, B, and G is 340, and the total firefighters in G is 20% more than in A, find the number of volunteer firefighters in G.
Answer (Detailed Solution Below)
Line Graph Question 5 Detailed Solution
General Solution:
Given: Total number of firefighters across all districts = 4200
Let the total number of firefighters in terms of x be:
District A = 6x
District B = 7.2x
District C = 9x
District D = 9.6x
District E = 10.2x
Add total firefighters across all districts:
6x + 7.2x + 9x + 9.6x + 10.2x = 42x
⇒ 42x = 4200
⇒ x = 4200 ÷ 42 = 100
Calculate total firefighters in each district using x = 100:
District A = 6 × 100 = 600
District B = 7.2 × 100 = 720
District C = 9 × 100 = 900
District D = 9.6 × 100 = 960
District E = 10.2 × 100 = 1020
Use difference between full-time and volunteer firefighters:
District A: Total = 600, Difference = 288
⇒ Let volunteer = a, then full-time = a + 288
⇒ a + (a + 288) = 600 ⇒ 2a + 288 = 600
⇒ 2a = 312 ⇒ a = 156
⇒ Volunteer = 156, Full-time = 444
District B: Total = 720, Difference = 120
⇒ Let volunteer = a, full-time = a + 120
⇒ 2a + 120 = 720 ⇒ 2a = 600 ⇒ a = 300
⇒ Volunteer = 300, Full-time = 420
District C: Total = 900, Difference = 180
⇒ Let volunteer = a, full-time = a + 180
⇒ 2a + 180 = 900 ⇒ 2a = 720 ⇒ a = 360
⇒ Volunteer = 360, Full-time = 540
District D: Total = 960, Difference = 336
⇒ Let volunteer = a, full-time = a + 336
⇒ 2a + 336 = 960 ⇒ 2a = 624 ⇒ a = 312
⇒ Volunteer = 312, Full-time = 648
District E: Total = 1020, Difference = 60
⇒ Let volunteer = a, full-time = a + 60
⇒ 2a + 60 = 1020 ⇒ 2a = 960 ⇒ a = 480
⇒ Volunteer = 480, Full-time = 540
Thus,
| District | Total | Full-time | Volunteer |
|---|---|---|---|
| A | 600 | 444 | 156 |
| B | 720 | 420 | 300 |
| C | 900 | 540 | 360 |
| D | 960 | 648 | 312 |
| E | 1020 | 540 | 480 |
Calculations:
Average full-time firefighters in districts A, B, and G = 340
Total full-time in A = 444 (from earlier)
Total full-time in B = 420 (from earlier)
Total firefighters in G = 20% more than in A
Use average formula:
⇒ 864 + G = 1020
⇒ G (full-time in G) = 1020 - 864 = 156
Find total firefighters in district G:
Total in A = 600
⇒ Total in G = 600 + 20% of 600 = 600 + 120 = 720
Find volunteer firefighters in G:
Total = Full-time + Volunteer
⇒ Volunteer = Total - Full-time = 720 - 156 = 564
Thus, the correct answer: 564
Top Line Graph MCQ Objective Questions
The line chart given below shows the profit percentage of a company on 5 different products P1, P2, P3, P4 and P5.
The expenditure of product P5 is Rs. 46000. What is the revenue of product P5?
Answer (Detailed Solution Below)
Line Graph Question 6 Detailed Solution
Download Solution PDFGIVEN:
From the chart
Profit percentage in P5 = 8%
Expenditure = Rs. 46000
FORMULA USED:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
CALCULATION:
Profit percentage = [(Revenue – Expenditure)/Expenditure] × 100
⇒ 8 = [(Revenue – 46000)/46000] × 100
⇒ Revenue – 46000 = 8 × 460
⇒ Revenue = 3680 + 46000
⇒ Revenue = 49680
Study the line graph and answer the question that follows.
The line graph represents the number of vehicles (in thousands) manufactured by two automobile companies A and B over the years from 2010 to 2015. The X-axis represents the years and the Y-axis represents number of vehicles in thousands.
(The data shown here is only for mathematical exercise. They do not represent the actual figures of the country.)
The average value of the vehicles manufactured by Company A is what per cent of the average value of the vehicles manufactured by Company B during 2010 to 2015?
Answer (Detailed Solution Below)
Line Graph Question 7 Detailed Solution
Download Solution PDFCalculation:
Total value of vehicles manufactured by company A during 2010 - 2015 = 260 + 218 + 224 + 179 + 266 + 348 = 1495
Average value of vehicles manufactured by company A during 2010 - 2015 = 1495/6 = 249.16 (in thousands)
Total value of vehicles manufactured by company B during 2010 - 2015 = 307 + 270 + 250 + 289 + 310 + 416 = 1842
Average value of vehicles manufactured by company B during 2010 - 2015 = 1842/6 = 307 (in thousands)
∴ Required percentage = 249.16/307 × 100 = 81.2%
The line chart given below shows the profit percentage of a company on 5 different products P1, P2, P3, P4 and P5.
The revenue of product P3 is Rs. 38100. What is expenditure of product P3?
Answer (Detailed Solution Below)
Line Graph Question 8 Detailed Solution
Download Solution PDFGiven:
The revenue of product P3 is Rs. 38100.
Formula used:
Profit% = (revenue – expenditure)/expenditure × 100
Calculation:
The revenue of product P3 is 38100,
Let expenditure be Rs. y.
⇒ Profit% = (revenue – expenditure)/expenditure × 100
⇒ 27 = (38100 – y)/y × 100
⇒ 27y = 3810000 – 100y
⇒ 127y = 3810000
⇒ y = 30000
∴ Expenditure of product P3 is Rs. 30000
A company has five plants for manufacturing spare parts. Each plant manufactures local quality and export quality.
What is the ratio of the production of local quality and export quality units of the highest manufacturing plant?
Answer (Detailed Solution Below)
Line Graph Question 9 Detailed Solution
Download Solution PDFCalculation:
Manufacturing capacity of plant A = 420 + 140 = 560
Manufacturing capacity of plant B = 350 + 150 = 500
Manufacturing capacity of plant C = 360 + 120 = 480
Manufacturing capacity of plant D = 440 + 80 = 520
Manufacturing capacity of plant E = 440 + 110 = 550
So,
Plant A has the highest manufacturing capacity.
In Plant A:
Local Quality = 420
Export Quality = 140
Thus,
Local quality : Export quality
⇒ 420 : 140 = 3 : 1
∴ The correct answer is option (1).
The line chart given below shows the ratio of imports to exports for a country for 5 consecutive years. Y1, Y2, Y3, Y4 and Y5.
If the exports for year Y3 is Rs. 35,000 crore, then what will be imported (in crores) for the year Y3?
Answer (Detailed Solution Below)
Line Graph Question 10 Detailed Solution
Download Solution PDFThe ratio of import and export for Y3 is 1.1
Also exports for year Y3 is Rs. 35000 crore
∴ Imports for year Y3 = 35000 × 1.1 = Rs. 38500 crore
The line chart shows the annual food grain production for a country. For how many years was the production higher than the average production of the period?
Answer (Detailed Solution Below)
Line Graph Question 11 Detailed Solution
Download Solution PDFCalculation
Average production = (100 + 180 + 160 + 230 + 150 + 200)/6 = 1020/6 = 170
Except for 2012, 2014 and 2016, all other year average is higher than the average.
The answer is 3.
The line chart given below shows the ratio of imports to exports for a country for 5 consecutive years Y1, Y2, Y3, Y4 and Y5.
the imports for year Y5 is Rs. 76000 crore, then what will be exports (in crores) for the year Y5?
Answer (Detailed Solution Below)
Line Graph Question 12 Detailed Solution
Download Solution PDFCalculation:
From the line chart,
Ratio of imports to exports in year Y5 = 0.95
⇒ Imports/Exports = 0.95
⇒ 76000/Exports = 0.95 = 95/100 = 19/20
⇒ Exports = 76000 × 20/19
∴ Exports = Rs. 80000 crore
The following line graph displays the ratio of exports to imports (in terms of money in ₹ crores) of company A from 2010 to 2015.
Study the graph carefully and answer the question based on the given line graph.
In how many years, the export of company A was more than the company's import?
Answer (Detailed Solution Below)
Line Graph Question 13 Detailed Solution
Download Solution PDFCalculation:
Ratio of export to import in 2010 = E : I = 9 : 10
Ratio of export to import in 2011 = E : I = 12 : 10
Ratio of export to import in 2012 = E : I = 7 : 10
Ratio of export to import in 2013 = E : I = 24 : 10
Ratio of export to import in 2014 = E : I = 35 : 10
Ratio of export to import in 2015 = E : I = 24 : 10
Hence, there are four observations in which the export of company A was more than the company A import
∴ The correct answer is four.
Based on the given graph, what is the percentage change in CO2 concentration from year 1995 to 2015?
Answer (Detailed Solution Below)
Line Graph Question 14 Detailed Solution
Download Solution PDFFrom the graph:
CO2 concentration in the year 1995 = 360
CO2 concentration in the year 2015 = 400
Hence,
Percentage change = [(400 – 360)/360] × 100
⇒ 40/360 × 100
⇒ 1/9 × 100 = 11.11%
∴ The percentage change in CO2 concentration is 11.11%.
Between years 2015 to years 2018, when per quintal import price was maximum?
Answer (Detailed Solution Below)
Line Graph Question 15 Detailed Solution
Download Solution PDFFormula Used:
Per quintal import price = Total Cost/Total Quantity
Calculation:
In the year 2015 = 60/6 = 10
In the year 2016 = 36/9 = 4
In the year 2017 = 100/12 = 8.33
In the year 2018 = 20/6 = 3.33
In the year 2015 per quintal import price was maximum.
The correct option is 1 i.e. 2015